Question

我正在做一个显示几个素数的程序，是使用函数所必需的。例如，1 = 10 = 2,3,5,7

但在 - 打印i-的最后一行出现错误...我无法理解那是什么

def isPrime(num):
    if num < 2:
        return False

    i = 2
    for i in range(2,int(math.sqrt(num)+1)):
        if (num % i == 0):
            return False

    return True

def main():
    print ("this program do prime numbers")
    start = int(raw_input("start number "))
    finish = int(raw_input('finish number: '))

    for i in range(start,finish):
        if isPrime(i):
            print i

Answer 1

您的问题是您没有围绕i括号中的print i。 In Python 3, print has been changed from a statement to a function.以下是您编辑的代码：

def isPrime(num):
    if num < 2:
        return False

    i = 2
    for i in range(2,int(math.sqrt(num)+1)):
        if (num % i == 0):
            return False

    return True

def main():
    print ("this program do prime numbers")
    start = int(raw_input("start number "))
    finish = int(raw_input('finish number: '))

    for i in range(start,finish):
        if isPrime(i):
            print(i) #Previously "print i"

之前正在运行：

bash-3.2$ python3.4 prime.py
  File "test.py", line 19
    print i
          ^
SyntaxError: invalid syntax
bash-3.2$

编辑后：

bash-3.2$ python3.4 prime.py
bash-3.2$

Python 3.4.1语法无效？

1 个答案: