Question

我有这样的PHP代码：

<?php
class MyDestructableClass {
   function __destruct() {
       print "Destroying MyDestructableClass";
       throw new Exception('Intentionally thrown exception, can it be caught?');
   }
}

$obj = new MyDestructableClass();

exit;  // Triggers destructor eventually

?>

当exit（）发生时，我想在析构函数发生时打印一条特殊的消息（并抛出异常）。我无法修改MyDestructableClass本身的内容，我只想注意它的析构函数何时抛出异常。

我尝试过一个异常处理程序：

<?php
class MyDestructableClass {
   function __destruct() {
       print "Destroying MyDestructableClass";
       throw new Exception('Intentionally thrown exception, can it be caught?');
   }
}

$obj = new MyDestructableClass();

function myExceptionHandler($exception)
{
  print "I noticed an exception was thrown, success!";
}

set_exception_handler('myExceptionHandler');

exit;  // Triggers destructor eventually

?>

但没有打印。

我也尝试过关机功能：

<?php
class MyDestructableClass {
   function __destruct() {
       print "Destroying MyDestructableClass";
       throw new Exception('Intentionally thrown exception, can it be caught?');
   }
}

$obj = new MyDestructableClass();

function myShutdownFunction()
{
  if (error_get_last() != NULL)  // Only want to react to errors, not normal shutdown
  {
    print "I noticed an exception was thrown, success!";
  }
}

register_shutdown_function('myShutdownFunction');

exit;  // Triggers destructor eventually

?>

但没有打印。

什么技术可以注意到由exit（）启动的析构函数中的异常？

Answer 1

这对我有用。但我不知道这是不是你想要的。

<?php

class MyDestructableClass {
    function __destruct() {
        print "Destroying MyDestructableClass";
        throw new Exception('Intentionally thrown exception, can it be caught?');
    }
}


function RunEverything(){
    $obj = new MyDestructableClass();
}

try {
    RunEverything();

} catch (Exception $e){
    echo 'My error has been thrown';
}


exit;
/*
 */

?

如何在php中的exit（）触发的析构函数中抛出异常时打印消息？

1 个答案: