简单的c ++计算器与sqrt和pow？

Question

你好我是c ​​++的初学者，我想写一个简单的c ++计算器，我写了这个程序，我不知道如何添加pow和sqrt，请帮助我，

#include<conio.h>
#include<iostream>
#include<math.h>

using namespace std;
main()
{
    double num1 , num2 ;
    char op ;
    while(1)
    {
        cout<<"type number,operator,number"<<endl;
        cin>>num1>>op>>num2;
        switch(op)
        {
        case '+':
            cout<<"plural is "<<num1+num2<<endl;
            break ;
        case '-':
            cout<<"subtract is "<<num1-num2<<endl;
            break ;
        case '*':
        case 'x':
            cout<<"multiple is "<<num1*num2<<endl;
            break ;
        case '/':
        case '\\':
            cout<<"division is "<<num1/num2<<endl;
            break ;
        default:
            cout<<"operator is illegal"<<endl;
        }
    }
}

Answer 1

只需使用cmath（或math.h中提供的函数，就像您已经包含的那样）：

cout << "square root of  " << num1 << ": " << sqrt(num1);

...

cout << num1 << " raised to the power " << num2 << ": " << pow(num1, num2);

Answer 2

您可以添加几个案例：

case 'r':       // For radicals
    cout << pow(num1, 1.0/num2);   // Note that if num2 == 2 this is the same as sqrt.
case 'p':       // For pow
    cout << pow(num1, num2);

请记住：

Answer 3

在switch

中再添加两个案例

case '^':
cout<<"Power is "<<pow(num1,num2);
break;

和

case 's': // you can't type in the sqrt symbol directly
cout<<"sqrt of num1:"<<sqrt(num1)<<"\nsqrt of num2:"<<sqrt(num2);