Question

我很担心这个GROUP BY＆amp;联盟声明。

现在我得到这个O / P.

enter image description here

但我希望我的输出看起来像这样：

   Vendor Name          Purchase Order         Req Qty        Inward Qty
   ----------------------------------------------------------------------       
   Philips Lighting      PO20140918133011        350             350
   (I) Pvt Ltd

要求：

如果我的供应商为空，那么我也必须根据采购订单进行分组。但是我得到的所有要求都不满足的输出有没有办法我只能根据采购订单进行分组。

**查询：**

SELECT
    vendor_name,
    purchase_order_no,  
    SUM(ISNULL(InwardQty,0)) AS InwardQty,
    SUM(ISNULL(ReqQty,0)) ReqQty
FROM
(
    SELECT 
        vendor_name,
        pm.purchase_order_no,
        ISNULL(SUM(PIIM.qty),0) AS ReqQty,
        0 InwardQty
    FROM  
        RS_Purchase_Order_Master AS PM
        LEFT OUTER JOIN RS_Purchase_Invoice_Info_Master AS PIIM ON PIIM.purchase_order_no = PM.purchase_order_no
        LEFT OUTER JOIN RS_Vendor_Master AS VM ON VM.vendor_id = PM.vendor_id
    WHERE 
        IsPicreated = 1
    GROUP BY 
        vendor_name,
        pm.purchase_order_no

    UNION

    SELECT
        NULL AS vendor_name,
        purchase_order_no,
        0 AS ReqQty,
        ISNULL(SUM(qty),0) AS InwardQty
    FROM
        RS_GIN_Master       
    GROUP BY
        purchase_order_no
)
AS A
GROUP BY
    vendor_name,
    purchase_order_no

任何帮助或建议都会受到赞赏。

提前谢谢

Answer 1

我不知道这是否是最佳解决方案，但我会创建一个临时表（@a）：

declare @a table (
purchase_order_no varchar(100),
TotalReqQty int,
TotalInwardQty int )

插入结果：

SELECT  purchase_order_no, 
   SUM(ReqQty), 
   SUM(InwardQty)
FROM table 
group by purchase_order_no

之后我会使用内部联接来使用这样的东西来获取供应商：

SELECT T.Vendor_Name,
   A.purchase_order_no, 
   A.TotalReqQty,
   A.TotalInwardQty
FROM @a a
inner join 
( SELECT DISTINCT Vendor_Name, purchase_order_no
  FROM table WHERE Vendor_Name IS NOT NULL ) T
    ON A.purchase_order_no = T.purchase_order_no

Answer 2

您无需创建临时表。只需从GROUP BY中删除vendor_name，然后添加MAX（vendor_name）。

SELECT
    MAX(vendor_name) AS vendor_name,
    purchase_order_no,  
    SUM(ISNULL(InwardQty,0)) AS InwardQty,
    SUM(ISNULL(ReqQty,0)) AS ReqQty
FROM
(
    SELECT 
        vendor_name,
        pm.purchase_order_no,
        ISNULL(SUM(PIIM.qty),0) AS ReqQty,
        0 InwardQty
    FROM  
       RS_Purchase_Order_Master AS PM
       LEFT OUTER JOIN RS_Purchase_Invoice_Info_Master AS PIIM ON PIIM.purchase_order_no = PM.purchase_order_no
       LEFT OUTER JOIN RS_Vendor_Master AS VM ON VM.vendor_id = PM.vendor_id
    WHERE 
        IsPicreated = 1
    GROUP BY 
        vendor_name,
        pm.purchase_order_no

    UNION

    SELECT
        NULL AS vendor_name,
        purchase_order_no,
        0 AS ReqQty,
        ISNULL(SUM(qty),0) AS InwardQty
    FROM
        RS_GIN_Master       
    GROUP BY
        purchase_order_no
)
AS A
GROUP BY
    purchase_order_no

Answer 3

如果我查看您的查询：

子查询中的联盟 - ＆gt;在每个purchase_order_no的表RS_GIN_Master中得到sum（qty）

子查询 - ＆gt;将2行设为单行。

试试这个：

SELECT 
    vendor_name,
    pm.purchase_order_no,
    ISNULL(SUM(PIIM.qty),0) AS ReqQty,
    sum(xx.InwardQty) as InwardQty
FROM  
    RS_Purchase_Order_Master AS PM
    LEFT OUTER JOIN RS_Purchase_Invoice_Info_Master AS PIIM ON PIIM.purchase_order_no =      PM.purchase_order_no
    LEFT OUTER JOIN RS_Vendor_Master AS VM ON VM.vendor_id = PM.vendor_id
    LEFT JOIN (
                SELECT purchase_order_no, ISNULL(SUM(qty),0) AS InwardQty
                FROM RS_GIN_Master  
                GROUP BY purchase_order_no
            ) xx On xx.purchase_order_no = pm.purchase_order_no
WHERE 
    IsPicreated = 1
GROUP BY 
    vendor_name,
    pm.purchase_order_no

分组和＆amp;联盟在Sql中

3 个答案: