当我尝试编译此代码时,我不断收到错误消息:
line 13: Error, 'std_logic' is not a known type.
第13行是Clock : IN std_logic;
实体中的ALU_tb
。
我对此错误感到困惑,因为我的理解是所述错误的原因通常是缺少库/包。我几乎可以肯定我有适当的库和包。另外,std_logic类型的其他信号都没有出错。
如果有人能帮助我解决这个问题,我将非常感激。
-- VHDL Entity ALU.ALU_tb.symbol
--
-- Created:
-- by - ClarkG.UNKNOWN (COELABS15)
-- at - 19:58:20 09/ 8/2014
--
-- Generated by Mentor Graphics' HDL Designer(TM) 2011.1 (Build 18)
--
ENTITY ALU_tb IS
PORT(
Clock : IN std_logic;
Reset_N : IN std_logic
);
-- Declarations
END ALU_tb ;
--
-- VHDL Architecture ALU.ALU_tb.struct
--
-- Created:
-- by - ClarkG.UNKNOWN (COELABS15)
-- at - 19:58:20 09/ 8/2014
--
-- Generated by Mentor Graphics' HDL Designer(TM) 2011.1 (Build 18)
--
LIBRARY ieee;
USE ieee.std_logic_1164.ALL;
USE ieee.std_logic_arith.ALL;
LIBRARY ALU;
ARCHITECTURE struct OF ALU_tb IS
-- Architecture declarations
-- Internal signal declarations
SIGNAL A : std_logic_vector(31 DOWNTO 0);
SIGNAL ALUOp : std_logic_vector(3 DOWNTO 0);
SIGNAL B : std_logic_vector(31 DOWNTO 0);
SIGNAL Overflow : std_logic;
SIGNAL R : std_logic_vector(31 DOWNTO 0);
SIGNAL SHAMT : std_logic_vector(4 DOWNTO 0);
SIGNAL Zero : std_logic;
-- Component Declarations
COMPONENT ALU
PORT (
A : IN std_logic_vector (31 DOWNTO 0);
ALUOp : IN std_logic_vector (3 DOWNTO 0);
B : IN std_logic_vector (31 DOWNTO 0);
SHAMT : IN std_logic_vector (4 DOWNTO 0);
Overflow : OUT std_logic ;
R : OUT std_logic_vector (31 DOWNTO 0);
Zero : OUT std_logic
);
END COMPONENT;
COMPONENT ALU_tester
PORT (
A : IN std_logic_vector (31 DOWNTO 0);
ALUOp : IN std_logic_vector (3 DOWNTO 0);
B : IN std_logic_vector (31 DOWNTO 0);
Clock : IN std_logic ;
Overflow : IN std_logic ;
R : IN std_logic_vector (31 DOWNTO 0);
Reset_N : IN std_logic ;
SHAMT : IN std_logic_vector (4 DOWNTO 0);
Zero : IN std_logic
);
END COMPONENT;
COMPONENT Test_transaction_generator
PORT (
Clock : IN std_logic ;
A : OUT std_logic_vector (31 DOWNTO 0);
ALUOp : OUT std_logic_vector (3 DOWNTO 0);
B : OUT std_logic_vector (31 DOWNTO 0);
SHAMT : OUT std_logic_vector (4 DOWNTO 0)
);
END COMPONENT;
-- Optional embedded configurations
-- pragma synthesis_off
FOR ALL : ALU USE ENTITY ALU.ALU;
FOR ALL : ALU_tester USE ENTITY ALU.ALU_tester;
FOR ALL : Test_transaction_generator USE ENTITY ALU.Test_transaction_generator;
-- pragma synthesis_on
BEGIN
-- Instance port mappings.
U_0 : ALU
PORT MAP (
A => A,
ALUOp => ALUOp,
B => B,
SHAMT => SHAMT,
Overflow => Overflow,
R => R,
Zero => Zero
);
U_1 : ALU_tester
PORT MAP (
A => A,
ALUOp => ALUOp,
B => B,
Clock => Clock,
Overflow => Overflow,
R => R,
Reset_N => Reset_N,
SHAMT => SHAMT,
Zero => Zero
);
U_2 : Test_transaction_generator
PORT MAP (
Clock => Clock,
A => A,
ALUOp => ALUOp,
B => B,
SHAMT => SHAMT
);
END struct;
答案 0 :(得分:2)
由库子句和use子句组成的context子句应该在实体声明之前而不是在体系结构体之前移动。实体和体系结构形成一个公共声明区域,允许这些库和使用子句在两者之间生效,而不仅仅是体系结构,就像在您的代码中一样。
您似乎也没有在您显示的代码中使用包std_logic_arith。 (该架构仅包含组件)。
答案 1 :(得分:1)
在第13行,您尚未导入定义std_logic所需的ieee库,这就是您收到错误的原因。