Question

我有一个Ajax / PHP代码，我想检查返回的文本是真还是假：

$(".gets").click(function() {

    // some details

    $.ajax({
        type: "POST",
        url: "step2.php",
        data: dataString,
        success: function(data) {

            // This is the button to hide
            $('.nums').fadeOut('fast');

        } // end function
    }); // end ajax  

    return false;
});

step2.php

if($num < 3) {
echo 'please choose at least 3 nums<br />';
$hideButton = false; // hide show nums button
} else {        
$hideButton = true;
}

提前致谢

Answer 1

你必须回复$hideButton。该信息将在data

中提供

if($num < 3) {
echo 'please choose at least 3 nums<br />';
    $hideButton = false; // hide show nums button
} else {        
    $hideButton = true;
}
echo $hideButton;

然后 -

$.ajax({
   type: "POST",
   url: "step2.php",
   data: dataString,
   success: function(data) { // data now has the value of $hideButton
       if(data == 'true') {
          // This is the button to hide
          $('.nums').fadeOut('fast');
       }
    } // end function
}); // end ajax

Answer 2

$(".gets").click(function() {

// some details

$.ajax({
type: "POST",
url: "step2.php",
data: dataString,
success: function(data) {
              if(data == 'true')
                   {// your if code
                      }
             else
                  {// your else code
                   }

    // This is the button to hide
    $('.nums').fadeOut('fast');
} // end function
    }); // end ajax        
return false;
 });

Answer 3

尝试更改下面的脚本。

在AJAX success

success: function(data) {
   if(data == 'false'){
      $('.nums').fadeOut('fast');
   }else{
      // other event if you want
   }

在step2.php

echo ( $num < 3 ) ? 'false' : 'true';

检查返回的文本是真还是假

3 个答案: