Question

我的代码中有一个名为'match3g'的字符串值，它以下列格式打印数据：

10272,201,Halifax,1,3333,1,33,2,33
,10272,989,Forest Green,2,3331,3,33,9,31
,10272,203,Lincoln,3,1333,6,13,4,33
,10272,206,Barnet,4,3303,11,30,1,33
,10272,199,Wrexham,5,3033,15,03,3,33
,10272,749,Kidderminster,6,1331,2,33,13,11
,10272,205,Macclesfield,7,3311,8,31,8,31
,10272,6106,Eastleigh,8,3310,7,31,10,30
,10272,1392,Aldershot,9,3031,5,31,12,03
,10272,921,Gateshead,10,3310,16,30,6,31
,10272,164,Grimsby,11,1113,18,11,5,13
,10272,991,Woking,12,3111,19,11,7,31
,10272,204,Torquay,13,0311,4,31,17,01
,10272,919,Southport,14,0013,14,03,18,01
,10272,185,Bristol Rovers,15,1003,9,13,22,00
,10272,909,Dover,16,0013,13,03,19,01
,10272,3551,Braintree Town,17,0300,10,30,20,00
,10272,1389,Altrincham,18,0030,12,03,21,00
,10272,213,Chester,19,0030,24,00,11,03
,10272,6140,Dartford,20,0101,20,01,15,10
,10272,1395,Welling,21,1001,17,11,24,00
,10272,982,Telford,22,1000,22,00,14,10
,10272,913,Nuneaton,23,0100,23,00,16,10
,10272,2792,Alfreton,24,0000,21,00,23,00

我想用逗号分隔每行第4个逗号之后的数字字符串。我有一些代码可以实现这一点，但只解析最后一行：

regex2 = re.compile(r'\d+(?=(?:,[^,]+){4}$)',re.S)
regexer2 = re.search(regex2, match3g)
regexer2 = regexer2.group()
regexer3 = ','.join(list(regexer2))
regexs2 = str(regexer3)
print "Test = ", regexs2.decode()

打印结果：

Test = 0,0,0,0

但是我希望'match3g'中的每一行数据都采用相同的步骤。因此，我尝试使用'For'循环如下：

for line in match3g:
                regex2 = re.compile(r'\d+(?=(?:,[^,]+){4}$)',re.S)
                regexer2 = re.search(regex2, match3g)
                if regexer2 is not None:
                    regexer2 = regexer2.group()
                    regexer3 = ','.join(list(regexer2))
                    regexs2 = str(regexer3)
                    print "Test = ", regexs2.decode()

而不是给我想要的结果，我得到这样的打印：

Test - 0,0,0,0
Test - 0,0,0,0
Test - 0,0,0,0
Test - 0,0,0,0
....lots of lines of this
Test - 0,0,0,0
Test - 0,0,0,0
Test - 0,0,0,0
Test - 0,0,0,0

我的预期输出是：

Test = 3,3,3,3
Test = 3,3,3,1
Test = 1,3,3,3
Test = 3,3,0,3
Test = 3,0,3,3
Test = 1,3,3,1
Test = 3,3,1,1
Test = 3,3,1,0
Test = 3,0,3,1
Test = 3,3,1,0
Test = 1,1,1,3
Test = 3,1,1,1
Test = 0,3,1,1
Test = 0,0,1,3
Test = 1,0,0,3
Test = 0,0,1,3
Test = 0,3,0,0
Test = 0,0,3,0
Test = 0,0,3,0
Test = 0,1,0,1
Test = 1,0,0,1
Test = 1,0,0,0
Test = 0,1,0,0
Test = 0,0,0,0

任何人都可以看到我出错的地方吗？它看起来好像我几乎就在那里。

由于

Answer 1

for line in s.split("\n"):
    spl = line.rsplit(",",5)[-5:-4]
    if spl:
        print "Test = {}".format(",".join(list(spl[0])))
Test = 3,3,3,3
Test = 3,3,3,1
Test = 1,3,3,3
Test = 3,3,0,3
Test = 3,0,3,3
Test = 1,3,3,1
Test = 3,3,1,1
Test = 3,3,1,0
Test = 3,0,3,1
Test = 3,3,1,0
Test = 1,1,1,3
Test = 3,1,1,1
Test = 0,3,1,1
Test = 0,0,1,3
Test = 1,0,0,3
Test = 0,0,1,3
Test = 0,3,0,0
Test = 0,0,3,0
Test = 0,0,3,0
Test = 0,1,0,1
Test = 1,0,0,1
Test = 1,0,0,0
Test = 0,1,0,0
Test = 0,0,0,0

Answer 2

我想你可能想要这个，如果你想要0,0,0,0而不是0000。

#!/usr/bin/python
#-*- coding:utf-8 -*-

import re

match3g = '''10272,201,Halifax,1,3333,1,33,2,33
,10272,989,Forest Green,2,3331,3,33,9,31
,10272,203,Lincoln,3,1333,6,13,4,33
,10272,206,Barnet,4,3303,11,30,1,33
,10272,199,Wrexham,5,3033,15,03,3,33
,10272,749,Kidderminster,6,1331,2,33,13,11
,10272,205,Macclesfield,7,3311,8,31,8,31
,10272,6106,Eastleigh,8,3310,7,31,10,30
,10272,1392,Aldershot,9,3031,5,31,12,03
,10272,921,Gateshead,10,3310,16,30,6,31
,10272,164,Grimsby,11,1113,18,11,5,13
,10272,991,Woking,12,3111,19,11,7,31
,10272,204,Torquay,13,0311,4,31,17,01
,10272,919,Southport,14,0013,14,03,18,01
,10272,185,Bristol Rovers,15,1003,9,13,22,00
,10272,909,Dover,16,0013,13,03,19,01
,10272,3551,Braintree Town,17,0300,10,30,20,00
,10272,1389,Altrincham,18,0030,12,03,21,00
,10272,213,Chester,19,0030,24,00,11,03
,10272,6140,Dartford,20,0101,20,01,15,10
,10272,1395,Welling,21,1001,17,11,24,00
,10272,982,Telford,22,1000,22,00,14,10
,10272,913,Nuneaton,23,0100,23,00,16,10
,10272,2792,Alfreton,24,0000,21,00,23,00'''


for line in match3g.split('\n'):
    a = line.split(',')
    if a[0]=='':
        print list(a[5])
    else:
        print list(a[4])

Answer 3

用OP评论后重写：

我对Python不太满意，很抱歉如果我在python部分错了：

#!/usr/bin/python
#-*- coding:utf-8 -*-

import re

match3g = '''10272,201,Halifax,1,3333,1,33,2,33
,10272,989,Forest Green,2,3331,3,33,9,31
,10272,203,Lincoln,3,1333,6,13,4,33
,10272,206,Barnet,4,3303,11,30,1,33
,10272,199,Wrexham,5,3033,15,03,3,33
,10272,749,Kidderminster,6,1331,2,33,13,11
,10272,205,Macclesfield,7,3311,8,31,8,31
,10272,6106,Eastleigh,8,3310,7,31,10,30
,10272,1392,Aldershot,9,3031,5,31,12,03
,10272,921,Gateshead,10,3310,16,30,6,31
,10272,164,Grimsby,11,1113,18,11,5,13
,10272,991,Woking,12,3111,19,11,7,31
,10272,204,Torquay,13,0311,4,31,17,01
,10272,919,Southport,14,0013,14,03,18,01
,10272,185,Bristol Rovers,15,1003,9,13,22,00
,10272,909,Dover,16,0013,13,03,19,01
,10272,3551,Braintree Town,17,0300,10,30,20,00
,10272,1389,Altrincham,18,0030,12,03,21,00
,10272,213,Chester,19,0030,24,00,11,03
,10272,6140,Dartford,20,0101,20,01,15,10
,10272,1395,Welling,21,1001,17,11,24,00
,10272,982,Telford,22,1000,22,00,14,10
,10272,913,Nuneaton,23,0100,23,00,16,10
,10272,2792,Alfreton,24,0000,21,00,23,00'''


regex2 = re.compile(r'^(?:,|)(?:.*?,){4}(\d+),.*$',re.M)
for (line) in match3g.split('\n'):
  print line
  match = re.search(regex2, line)
  print list(match.group(1))

对于具有正则表达式的循环，其行为不符合要求

3 个答案: