错误:java.util.NoSuchElementException - 扫描程序无法按预期运行

时间:2013-06-11 05:17:25

标签: java algorithm loops if-statement java.util.scanner

扫描仪返回NoSuch Element Exception错误。你能解释一下为什么会这样吗。

扫描仪现在通过并运行正常,但它没有从第二个扫描仪调用中获取nextLine输入。这可能是一个小调整,但有人可以指出错误是什么。

public class JavaHW1_1 {

private static Scanner userInput = new Scanner(System.in);


public static void main(String[] args) throws IOException {

    String pattern ;
    String fileName = null;



    //      Method to manage user inputs 
    fileName = userInputFileName(userInput);
    pattern = userInputPattern(userInput);

    //      To find the pattern in the file
    //      findPattern();

}


private static String userInputPattern(Scanner userInput) {
    String pattern = "JollyGood";
    System.out.println(". Please enter a pattern to find in the file");

    while(userInput.hasNextLine()){
        pattern = userInput.nextLine();
        System.out.println("The pattern to be searched: "+ pattern);
    }
    userInput.close();

    return pattern;
}


private static String userInputFileName(Scanner userInput) throws IOException {
    String path = "./src";
    String files, fileName;
    File folder = new File(path);
    File[] listOfFiles = folder.listFiles();

    System.out.println("Please input the desired file name:\n");
    System.out.println("Some suggestions:\n");
     for (int i = 0; i < listOfFiles.length; i++) 
      {

       if (listOfFiles[i].isFile() && listOfFiles[i].getName().toLowerCase().endsWith(".txt")) 
       {

       files = listOfFiles[i].getName();
       System.out.println(files);
          }
      }

     int userAttempt = 0;

     do{
     fileName = userInput.nextLine();

     if(fileName.toLowerCase().endsWith(".txt")){
         System.out.println("The file name entered is in correct format");
         File file = new File("./src",fileName);

         try {
            file.createNewFile();
            System.out.println("File is created. Please enter text to be written in the file. End the content with \"eof\"");
            InputOutput(file.getName());
        } catch (IOException e) {
            e.printStackTrace();
        }

         userAttempt = 10;
     }
     else
         {System.out.println("Please enter correct format file with .txt extension");
         userAttempt++;}
     }while (userAttempt <10);

    return fileName;
}




private static void InputOutput(String fName) throws IOException {

    BufferedReader in = new BufferedReader(new InputStreamReader(System.in));

    BufferedWriter out = null;
    try {
        out = new BufferedWriter(new FileWriter("./src/" + fName));
        String inputLine = null;
        do {
            inputLine=in.readLine();
            out.write(inputLine);
            out.newLine();
        } while (!inputLine.equalsIgnoreCase("aaa"));
        System.out.print("Write Successful");
    } catch(IOException e1) {
        System.out.println("Error during reading/writing");
    } finally {
        out.close();
        in.close();
    }

}


private static void findPattern() {
    // TODO Auto-generated method stub

}


}

2 个答案:

答案 0 :(得分:1)

基于this SO,您可能正在关闭Scanner并创建一个新版本以便从System.in中读取,并且通过查看您的代码就可以了。

所以我对你的代码建议是通过参数接收Scanner,如下所示:

public static void main(String[] args){

    Scanner scan = new Scanner (System.in);
    String pattern = userInputPattern(scan);
    String test = readSomethingElse(scan);
}

private static String readSomethingElse(Scanner scan) {
   System.out.println(". Read something else");
    return scan.nextLine();
}

private static String userInputPattern(Scanner scan) {

    String pattern = "JollyGood";
    System.out.println(". Please enter a pattern to find in the file");
    pattern = scan.nextLine();
    System.out.println("The pattern to be searched: "+ pattern);
    return pattern;
}

答案 1 :(得分:0)

如果您将EOF直接传递到标准输入,可能会发生这种情况。例如(在Windows中):

java com.myprog.MainClass
^Z
Exception in thread "main" java.util.NoSuchElementException: No line found
  at java.util.Scanner.nextLine(Unknown Source)
  ....

上面的^ Z表示Windows命令提示符上的Ctrl-Z,它是一个EOF信号

如果向用户提供了没有任何先前数据的EOF,则需要考虑您的要求和处理/显示错误