扫描仪返回NoSuch Element Exception错误。你能解释一下为什么会这样吗。
扫描仪现在通过并运行正常,但它没有从第二个扫描仪调用中获取nextLine输入。这可能是一个小调整,但有人可以指出错误是什么。
public class JavaHW1_1 {
private static Scanner userInput = new Scanner(System.in);
public static void main(String[] args) throws IOException {
String pattern ;
String fileName = null;
// Method to manage user inputs
fileName = userInputFileName(userInput);
pattern = userInputPattern(userInput);
// To find the pattern in the file
// findPattern();
}
private static String userInputPattern(Scanner userInput) {
String pattern = "JollyGood";
System.out.println(". Please enter a pattern to find in the file");
while(userInput.hasNextLine()){
pattern = userInput.nextLine();
System.out.println("The pattern to be searched: "+ pattern);
}
userInput.close();
return pattern;
}
private static String userInputFileName(Scanner userInput) throws IOException {
String path = "./src";
String files, fileName;
File folder = new File(path);
File[] listOfFiles = folder.listFiles();
System.out.println("Please input the desired file name:\n");
System.out.println("Some suggestions:\n");
for (int i = 0; i < listOfFiles.length; i++)
{
if (listOfFiles[i].isFile() && listOfFiles[i].getName().toLowerCase().endsWith(".txt"))
{
files = listOfFiles[i].getName();
System.out.println(files);
}
}
int userAttempt = 0;
do{
fileName = userInput.nextLine();
if(fileName.toLowerCase().endsWith(".txt")){
System.out.println("The file name entered is in correct format");
File file = new File("./src",fileName);
try {
file.createNewFile();
System.out.println("File is created. Please enter text to be written in the file. End the content with \"eof\"");
InputOutput(file.getName());
} catch (IOException e) {
e.printStackTrace();
}
userAttempt = 10;
}
else
{System.out.println("Please enter correct format file with .txt extension");
userAttempt++;}
}while (userAttempt <10);
return fileName;
}
private static void InputOutput(String fName) throws IOException {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter out = null;
try {
out = new BufferedWriter(new FileWriter("./src/" + fName));
String inputLine = null;
do {
inputLine=in.readLine();
out.write(inputLine);
out.newLine();
} while (!inputLine.equalsIgnoreCase("aaa"));
System.out.print("Write Successful");
} catch(IOException e1) {
System.out.println("Error during reading/writing");
} finally {
out.close();
in.close();
}
}
private static void findPattern() {
// TODO Auto-generated method stub
}
}
答案 0 :(得分:1)
基于this SO,您可能正在关闭Scanner
并创建一个新版本以便从System.in
中读取,并且通过查看您的代码就可以了。
所以我对你的代码建议是通过参数接收Scanner,如下所示:
public static void main(String[] args){
Scanner scan = new Scanner (System.in);
String pattern = userInputPattern(scan);
String test = readSomethingElse(scan);
}
private static String readSomethingElse(Scanner scan) {
System.out.println(". Read something else");
return scan.nextLine();
}
private static String userInputPattern(Scanner scan) {
String pattern = "JollyGood";
System.out.println(". Please enter a pattern to find in the file");
pattern = scan.nextLine();
System.out.println("The pattern to be searched: "+ pattern);
return pattern;
}
答案 1 :(得分:0)
如果您将EOF直接传递到标准输入,可能会发生这种情况。例如(在Windows中):
java com.myprog.MainClass
^Z
Exception in thread "main" java.util.NoSuchElementException: No line found
at java.util.Scanner.nextLine(Unknown Source)
....
上面的^ Z表示Windows命令提示符上的Ctrl-Z,它是一个EOF信号
如果向用户提供了没有任何先前数据的EOF,则需要考虑您的要求和处理/显示错误