Question

我想将字符串转换为datetime对象。我的代码运行良好：

from datetime import datetime, timedelta

time_str_now = str(input('Ingresar hora: '))
time_format = '%H:%M:%S'
time_now = datetime.strptime(time_str_now, time_format)
time_plus = int(input('Ingresar hora adicional: '))    

time_from_now = time_now + timedelta(minutes = time_plus)
fecha_hora = '{:%H:%M:%S}'.format(time_from_now)
print(fecha_hora)

打印：

Ingresar hora: 00:00:00
Ingresar hora adicional: 45
00:45:00

现在，我想提供一个选项来选择用户是否需要＆＃34;小时＆＃34;，＆＃34;分钟＆＃34;，＆＃34;秒＆＃34;或＆＃34;毫秒＆＃34;。我试过这个：

from datetime import datetime, timedelta

time_str_now = str(input('Ingresar hora: '))
time_format = '%H:%M:%S'
time_now = datetime.strptime(time_str_now, time_format)
time_plus = int(input('Ingresar hora adicional: '))

operador = str(input('Oparador: ')) #here is where the user shuld to select the input: hours, minutes, seconds, ...

time_from_now = time_now + timedelta(operador = time_plus) #here is where it should go: hours, minutes, seconds, ...
fecha_hora = '{:%H:%M:%S}'.format(time_from_now)
print(fecha_hora)

但我得到以下例外：

Traceback (most recent call last):
File "C:/Users/Tatiana/Documents/Python Projects/Pruebas1.py", line 10, in <module>

   time_from_now = time_now + timedelta(operador = time_plus)

   TypeError: 'operador' is an invalid keyword argument for this function

Answer 1

如果要将成员参数化为递增，则必须解压缩一个参数dict哪个键应该是kwarg到timedelta函数

>>> from datetime import datetime,timedelta
>>> op='days'
>>> increment_value=1
>>> dt_now = datetime.now()
>>> dt_now + timedelta(**{op:increment_value})
datetime.datetime(2014, 8, 15, 7, 40, 15, 519452)

此片段相当于

>>> dt_now + timedelta(days = 1)

这是因为dict将被解压缩并且每个项目将被翻译为timedelta函数的关键字参数

如何在Python中将str转换为日期运算符？

1 个答案: