Question

假设我有以下标志：

[Flags]
public enum Foo
{
    None = 0,
    Foo1 = 1,
    Foo2 = 2,
    Foo4 = 4,
    Foo8 = 8
}

现在我有一个变量foo：

var foo = Foo.Foo1 | Foo.Foo4;

我想得的是以下foo的倒置旗帜。这意味着这样的事情：

Foo.Foo2 | Foo.Foo8

我试过〜运算符。但由于我的枚举是一个int32值，它反转所有32位。但实际上我只需要反转我的Foo enum使用的位。

编辑： Foo1 | Foo4将等于以下位掩码：

00000000 00000000 00000000 00000101

如果使用〜运算符反转该位掩码，将得到以下结果：

11111111 11111111 11111111 11111010

我希望得到的结果是：

00000000 00000000 00000000 00001010

如你所见。我只是想通过Foo枚举反转USED位。不是整个32整数值的所有位。

Answer 1

你想要做的是组合枚举的所有值，然后用当前值的补码掩盖它。

        Foo value = Foo.Foo4;
        Foo allValues = (Foo)0;
        foreach (var v in Enum.GetValues(typeof(Foo)))
            allValues |= (Foo)v;
        var compliment = allValues & ~(value);

或者，您可以将这些值与Linq结合使用，并静态缓存它们以提高性能：

    public static class FooHelper
    {
        private readonly static Foo allValues = ((Foo[])Enum.GetValues(typeof(Foo))).Aggregate((Foo)0, (all, cur) => all | cur);

        public static Foo AllValues { get { return allValues ; } }
    }

然后是：

        var foo = Foo.Foo1 | Foo.Foo4;
        var compliment = FooHelper.AllValues & ~(foo);

更新

如果你想要一个泛型方法来组合枚举的所有标志值，你可以这样做：

var compliment = EnumHelper.GetAll<Foo>() & ~(value);

其中有关枚举的基本数据缓存在惰性参数化单例实例中：

/// <summary>
/// Contains generic utilities for enums, constrained for enums only.
/// </summary>
public sealed class EnumHelper : Enums<Enum>
{
    private EnumHelper()
    {
    }
}

/// <summary>
/// For use by EnumHelper, not for direct use.
/// </summary>
public abstract class Enums<TEnumBase> where TEnumBase : class, IConvertible
{
    // Generic singleton remembering basic properties about specified enums, cached for performance.
    sealed class DataSingleton<TEnum> where TEnum : struct, TEnumBase
    {
        static readonly DataSingleton<TEnum> instance = new DataSingleton<TEnum>();

        readonly bool isSigned;
        readonly TEnum allValues;
        readonly bool hasFlags;

        // Explicit static constructor to tell C# compiler
        // not to mark type as beforefieldinit
        static DataSingleton()
        {
        }

        DataSingleton()
        {
            isSigned = GetIsSigned();
            allValues = GetAll();
            hasFlags = GetHasFlags();
        }

        static bool GetHasFlags()
        {
            var attributes = typeof(TEnum).GetCustomAttributes(typeof(FlagsAttribute), false);
            return attributes != null && attributes.Length > 0;
        }

        static bool GetIsSigned()
        {
            var underlyingType = Enum.GetUnderlyingType(typeof(TEnum));
            bool isSigned = (underlyingType == typeof(long) || underlyingType == typeof(int) || underlyingType == typeof(short) || underlyingType == typeof(sbyte));
            bool isUnsigned = (underlyingType == typeof(ulong) || underlyingType == typeof(uint) || underlyingType == typeof(ushort) || underlyingType == typeof(byte));
            if (!isSigned && !isUnsigned)
                throw new InvalidOperationException();
            return isSigned;
        }

        static TEnum GetAll()
        {
            if (GetIsSigned())
            {
                long value = 0;
                foreach (var v in Enum.GetValues(typeof(TEnum)))
                    // Not sure I need the culture but Microsoft passes it in Enum.ToUInt64(Object value) - http://referencesource.microsoft.com/#mscorlib/system/enum.cs
                    value |= Convert.ToInt64(v, CultureInfo.InvariantCulture);
                return (TEnum)Enum.ToObject(typeof(TEnum), value);
            }
            else
            {
                ulong value = 0;
                foreach (var v in Enum.GetValues(typeof(TEnum)))
                    // Not sure I need the culture but Microsoft passes it in Enum.ToUInt64(Object value) - http://referencesource.microsoft.com/#mscorlib/system/enum.cs
                    value |= Convert.ToUInt64(v, CultureInfo.InvariantCulture);
                return (TEnum)Enum.ToObject(typeof(TEnum), value);
            }
        }

        public bool HasFlags { get { return hasFlags; } }

        public bool IsSigned { get { return isSigned; } }

        public TEnum AllValues { get { return allValues; } }

        public static DataSingleton<TEnum> Instance { get { return instance; } }
    }

    private static void ThrowOnEnumWithoutFlags<TEnum>(DataSingleton<TEnum> data) where TEnum : struct, TEnumBase
    {
        if (!data.HasFlags)
        {
            throw (new ArgumentException("The generic argument [<TEnum>] must be an enumeration with the [FlagsAttribute] applied.", "TEnum: " + typeof(TEnum).FullName));
        }
    }

    public static TEnum GetAll<TEnum>() where TEnum : struct, TEnumBase
    {
        var data = DataSingleton<TEnum>.Instance;
        ThrowOnEnumWithoutFlags<TEnum>(data);
        return data.AllValues;
    }
}

Answer 2

更优雅的解决方案是使用所有字段的掩码，并对其余字段执行XOR操作。通常，您首先在枚举中添加一个“全部”值（这样一来，如果添加了另一个值，您就不太可能忘记更新它），所以在您的情况下：

[Flags]
public enum Foo
{
    None = 0,
    Foo1 = 1,
    Foo2 = 2,
    Foo3 = 4,
    Foo4 = 8,
    All = Foo1 | Foo2 | Foo3 | Foo4 // magic starts here
}

var foo = Foo1 | Foo4;
var fooInverted = ~Foo.All ^ ~foo; // result: Foo2|Foo3

Answer 3

要反转单个Enum标志，请尝试

private Foo foos; 
private static void FlagInvert(Foo foo)
    {var res = foos.HasFlag(foo) ? foos &= ~foo : foos  |= foo;}

反转枚举标志

3 个答案: