我目前正在解析由另一个应用程序导出的csv文件。此应用程序以奇怪的方式导出数据。此出口来自accoutning,它看起来与此相似..
我正在试图找出一种方法来读取csv文件,然后拆分多个“所有帐户”值和“Amt”值,以便M200和300.89是另一个条目,M300和400.54是另一个条目,并且M400和100.00是另一个条目。因此,在将这一行插入数据库之后,我实际上应该有4行,如此...
这就是我目前正在阅读和插入数据库的方式。
List<RawData> data = new List<RawData>();
try
{
string text = File.ReadAllText(lblFileName.Text);
string[] lines = text.Split('\n');
int total = 0, reduced = 0;
foreach (string line in lines)
{
RawData temp = new RawData(line);
total++;
if (!(temp.FirstAccount.Length == 0 || temp.FirstAccount == "1ST-ACCT-NO"))
{
reduced++;
data.Add(temp);
}
}
}
catch (IOException ex)
{
Console.WriteLine("Unable to read file. " + ex.ToString());
MessageBox.Show(ex.ToString());
}
try
{
foreach (RawData rData in data)
{
tCarsInTransit cit = new tCarsInTransit
{
FIRST_ACCT_NO = rData.FirstAccount,
ACCOUNT_NO_DV = rData.AccountNoDv,
ACCT_NO = rData.AcctNo,
ACCT_NO_L = rData.AccNoL,
ACCT_NUM_DV = rData.AcctNumDv,
ACCT_PFX = rData.AcctPfx,
ACCT_PFX_PRT = rData.AcctPfxPrt,
ACCT_TYPE_DV = rData.AcctTypeDv,
ADV_NO = rData.AdvNo,
ALL_PRT_FLAG = rData.AllPrtFlag,
AMT = rData.Amt,
AMT_GLE = rData.AmtGle,
BASE_GLE = rData.BaseGle,
CNT_CAT = rData.CntCat,
COLD_PRT_FLAG = rData.ColdPrtFlag,
COST_DV = rData.CostDv,
COST_OVRD_FLAG_DV = rData.CostOvrdFlagDv,
CR_ACCT_DV = rData.CrAcctDv,
CR_ACCT_DV_GLE = rData.CrAcctDvGle,
CROSS_POSTING_FLAG = rData.CrossPostingFlag,
CROSS_POST_CAT = rData.CrossPostCat,
CTRL_NO = rData.CtrlNo,
CTRL_TYPE_DV = rData.CtrlTypeDv,
DESC_REQD_DV = rData.DescReqdDv,
DR_ACCT_DV = rData.DrAcctDv,
GL_DIST_ACCT_DV = rData.GLDistAcctDv,
GL_DIST_DV = rData.GLDistDv,
GRP_NO_DV = rData.GrpNoDv,
ID_PORT_DATE_TIME_FMT_CAT = rData.IdPortDateTimeFmtCat,
INACTIVITY_DV = rData.InactivityDv,
JOIN_COL = rData.JoinCol,
JRNL_DATE = rData.JrnlDate,
JRNL_PFX = rData.JrnlPfx
};
tCIT.tCarsInTransits.Add(cit);
tCIT.SaveChanges();
lblMessage.ForeColor = System.Drawing.Color.Green;
lblMessage.Text = "Finished uploading. ";
}
}
catch (DbEntityValidationException ex)
{
foreach (var eve in ex.EntityValidationErrors)
{
Console.WriteLine("Entity of type \"{0}\" in state \"{1}\" has the following validation errors:",
eve.Entry.Entity.GetType().Name, eve.Entry.State);
foreach (var ve in eve.ValidationErrors)
{
Console.WriteLine("- Property: \"{0}\", Error: \"{1}\"",
ve.PropertyName, ve.ErrorMessage);
}
}
throw;
}
我不知道如何做到这一点。以上内容当前将csv文件以与csv文件导出的完全相同的方式插入到Sql Server中。任何想法将不胜感激!谢谢!
编辑:这是RawData类。
class RawData
{
public string FirstAccount { get; set; }
public string AccountNoDv { get; set; }
public string AcctNo { get; set; }
public string AccNoL { get; set; }
public string AcctNumDv { get; set; }
public string AcctPfx { get; set; }
public string AcctPfxPrt { get; set; }
public string AcctTypeDv { get; set; }
public string AdvNo { get; set; }
public string AllPrtFlag { get; set; }
public string Amt { get; set; }
public string AmtGle { get; set; }
public string BaseGle { get; set; }
public string CntCat { get; set; }
public string ColdPrtFlag { get; set; }
public string CostDv { get; set; }
public string CostOvrdFlagDv { get; set; }
public string CrAcctDv { get; set; }
public string CrAcctDvGle { get; set; }
public string CrossPostingFlag { get; set; }
public string CrossPostCat { get; set; }
public string CtrlNo { get; set; }
public string CtrlTypeDv { get; set; }
public string DescReqdDv { get; set; }
public string DrAcctDv { get; set; }
public string GLDistAcctDv { get; set; }
public string GLDistDv { get; set; }
public string GrpNoDv { get; set; }
public string IdPortDateTimeFmtCat { get; set; }
public string InactivityDv { get; set; }
public string JoinCol { get; set; }
public string JrnlDate { get; set; }
public string JrnlPfx { get; set; }
public RawData(string csvString)
{
string[] citData = csvString.Replace(", ", "").Replace(".,", ".").Split(',');
try
{
FirstAccount = citData[0];
AccountNoDv = citData[1];
AcctNo = citData[2];
AccNoL = citData[3];
AcctNumDv = citData[4];
AcctPfx = citData[5];
AcctPfxPrt = citData[6];
AcctTypeDv = citData[7];
AdvNo = citData[8];
AllPrtFlag = citData[9];
Amt = citData[10];
AmtGle = citData[11];
BaseGle = citData[12];
CntCat = citData[13];
ColdPrtFlag = citData[14];
CostDv = citData[15];
CostOvrdFlagDv = citData[16];
CrAcctDv = citData[17];
CrAcctDvGle = citData[18];
CrossPostingFlag = citData[19];
CrossPostCat = citData[20];
CtrlNo = citData[21];
CtrlTypeDv = citData[22];
DescReqdDv = citData[23];
DrAcctDv = citData[24];
GLDistAcctDv = citData[25];
GLDistDv = citData[26];
GrpNoDv = citData[27];
IdPortDateTimeFmtCat = citData[28];
InactivityDv = citData[29];
JoinCol = citData[30];
JrnlDate = citData[31];
JrnlPfx = citData[32];
}
catch (Exception ex)
{
Console.WriteLine("Something went wrong. " + ex.ToString());
}
}
}
编辑2:图像中的AllAccounts实际上是'AccountNoDv',并且实际上有许多不同的字段具有像'AccountNoDv'(AllAccounts)这样的倍数,但我们可能会删除它们,因为这不是最终导出。截至目前,我最担心的两个领域是AccountNoDv和Amt。
答案 0 :(得分:1)
尝试这样的事情:
foreach (string line in lines)
{
RawData temp = new RawData(line);
var AllAccounts = temp.AccountNoDv.split(' ');
var Amts = temp.Amt.split(' ');
if (AllAccounts.Length() == Amts.Length() && Amts.Length() > 1) {
// We have multiple values!
reduced++;
for (int i = 0; i < AllAccounts.Length(); i++) {
RawData temp2 = RawDataCopy(temp); // Copy the RawData object
temp2.AccountNoDv = AllAccounts[i];
temp2.Amt = Amts[i];
total++;
data.Add(temp2);
}
}
else {
total++;
if (!(temp.FirstAccount.Length == 0 || temp.FirstAccount == "1ST-ACCT-NO"))
{
reduced++;
data.Add(temp);
}
}
}
和
private RawData RawDataCopy(RawData copyfrom) {
// Write a function here that returns an exact copy from the one provided
// You might have to create a parameterless constructor for RawData
RawData RawDataCopy = new RawData();
RawDataCopy.FirstAccount = copyfrom.FirstAccount;
RawDataCopy.AccountNoDv = copyfrom.AccountNoDv;
RawDataCopy.AcctNo = copyfrom.AcctNo;
// . . . . . . . .
RawDataCopy.JrnlPfx = copyfrom.JrnlPfx;
return RawDataCopy;
}
然后还向RawData类添加无参数构造函数:
public RawData()
{
}
实现ICloneable
界面并调用Clone()
函数而不是RawDataCopy
函数可能更为性感,但它可以解决这个问题。
答案 1 :(得分:0)
在Linq中,您可以使用SelectMany来增加列表中的元素数量。这是一个如何做到这一点的粗略例子。我假设AllAccounts和Amt中的子元素数量是相同的。更强大的解决方案将检查这些问题。
因此,在您加载数据列表之后:
var expandedData =
data.SelectMany(item =>
// split amount (will just return one item if no spaces)
item.Amt.Split(" ".ToCharArray())
// join this to the split of all accounts
.Zip(item.AllAccounts.Split(" ".ToCharArray()),
// return the joined item as a new anon object
(a,b) => new { amt=a, all=b }),
// take the original list item and the anon object and return our new item
(full,pair) => { full.Amt = pair.amt; full.AllAccounts = pair.all; return full; }));
现在,您将拥有一个数据项列表,其中多个项目已展开到列表中。
我没有要测试的测试数据,所以我可能会有一些小错字 - 但我提出了很多意见,以使Linq尽可能清晰。
以下是我在LinqPad中为自己写的简单示例,以确保我了解SelectMany的工作原理:
string [] list = { "a b c d","e","f g" };
var result = list.SelectMany((e) =>
e.Split(" ".ToCharArray()),
(o,item) => new { org = o, item = item}).Dump();