我正在寻找LINQ等效于MySQL的group_concat()
的Sybase LIST()它会转换:
User Hobby
--------------
Bob Football
Bob Golf
Bob Tennis
Sue Sleeping
Sue Drinking
要:
User Hobby
--------------
Bob Football, Golf, Tennis
Sue Sleeping, Drinking
答案 0 :(得分:17)
那是GroupBy运营商。你在使用LINQ to Objects吗?
以下是一个例子:
using System;
using System.Collections.Generic;
using System.Linq;
public class Test
{
static void Main()
{
var users = new[]
{
new { User="Bob", Hobby="Football" },
new { User="Bob", Hobby="Golf" },
new { User="Bob", Hobby="Tennis" },
new { User="Sue", Hobby="Sleeping" },
new { User="Sue", Hobby="Drinking" },
};
var groupedUsers = users.GroupBy(user => user.User);
foreach (var group in groupedUsers)
{
Console.WriteLine("{0}: ", group.Key);
foreach (var entry in group)
{
Console.WriteLine(" {0}", entry.Hobby);
}
}
}
}
这是分组 - 您可以自己管理其余部分吗?
答案 1 :(得分:5)
查看此解决方案是否可以帮助您:
List<User> users = new List<User>()
{
new User {Name = "Bob", Hobby = "Football" },
new User {Name = "Bob", Hobby = "Golf"},
new User {Name = "Bob", Hobby = "Tennis"},
new User {Name = "Sue", Hobby = "Sleeping"},
new User {Name = "Sue", Hobby = "Drinking"}
};
var groupedUsers = from u in users
group u by u.Name into g
select new
{
Name = g.First<User>().Name,
Hobby = g.Select(u => u.Hobby)
};
foreach (var user in groupedUsers)
{
Console.WriteLine("Name: {0}", user.Name);
foreach (var hobby in user.Hobby)
{
Console.WriteLine("Hobby: {0}", hobby);
}
}
答案 2 :(得分:4)
使用以下内容解决问题的_concat
方面:
static class EnumerableExtensions
{
public static String AsJoined( this IEnumerable<String> enumerable )
{
return AsJoined( enumerable, "," );
}
public static String AsJoined( this IEnumerable<String> enumerable, String separator )
{
return String.Join( separator, enumerable.ToArray() );
}
}
bruno conde和Jon Skeet的答案输出foreach可以成为:
Console.WriteLine( "User:\tHobbies");
foreach ( var group in groupedUsers )
Console.WriteLine( "{0}:\t{1}", group.Key, group.Select( g => g.Hobby ).AsJoined( ", " ) );
...你会得到你要求的精确结果输出格式(是的,我知道其他人已经解决了你的问题,但很难抗拒!)
答案 3 :(得分:3)
否则我们可以执行以下操作 -
var users = new[]
{
new { User="Bob", Hobby="Football" },
new { User="Bob", Hobby="Golf" },
new { User="Bob", Hobby="Tennis" },
new { User="Sue", Hobby="Sleeping" },
new { User="Sue", Hobby="Drinking" },
};
var userList = users.ToList();
var ug = (from user in users
group user by user.User into groupedUserList
select new { user = groupedUserList.Key, hobby = groupedUserList.Select(g =>g.Hobby)});
var ug2 = (from groupeduser in ug
select new{ groupeduser.user, hobby =string.Join(",", groupeduser.hobby)});
答案 4 :(得分:2)
在一个Linq声明中执行此操作。我无法推荐代码,但它表明可以完成。
var groupedUsers = from user in users
group user by user.User into userGroup
select new
{
User = userGroup.Key,
userHobies =
userGroup.Aggregate((a, b) =>
new { User = a.User, Hobby = (a.Hobby + ", " + b.Hobby) }).Hobby
}
;
foreach (var x in groupedUsers)
{
Debug.WriteLine(String.Format("{0} {1}", x.User, x.userHobies));
}
答案 5 :(得分:-1)
所有答案都不够好;
因为这是一个db查询,但我们所有人都只是在内存中这样做;
diff是内存中的某些操作会发生错误,无法转换为存储表达式;
var list = db.Users.GroupBy(s=>s.User).
select(g=>new{user=g.Key,hobbys=g.select(s=>s.Hobby)}); // you can just do that from db
var result=list.ToList(); // this is important,to query data to memory;
var result2 = result.select(g=>new{user=g.Key,hobbyes=string.join(",",g.hobbyes)}; //then,do what you love in memory