Question

我有一张表，

（请注意，此问题可能听起来像重复但在发布此问题之前我检查了其他问题...如果您在其他帖子中找到答案，建议我而不是 downvoting 。我保证只是删除它.thx）

|tid |name|age|sex|pack_id
 1   |Joe |57 |M  |77
 2   |Joe |57 |M  |77
 3   |Joe |57 |M  |89
 4   |Joe |57 |M  |89
 5   |Joe |57 |M  |94

 6   |Roy |98 |M  |7
 7   |Roy |98 |M  |8
 8   |Roy |98 |M  |9
 9   |Roy |98 |M  |7
 10  |Roy |98 |M  |7
 11  |Roy |98 |M  |7

 12  |Joe |46 |M  |96

 13  |Guh |97 |F  |1

 14  |Kin |68 |F  |33
 15  |Kin |68 |F  |37
 16  |Kin |68 |F  |37
 17  |Kin |68 |F  |37
 18  |Kin |68 |F  |35
 19  |Kin |68 |F  |37

 20  |Pit |43 |F  |77
 21  |Pit |43 |F  |1
 22  |Pit |43 |F  |2
 23  |Pit |43 |F  |1
 24  |Pit |43 |F  |77

 25  |Joe |71 |M  |75

 26  |Bob |82 |M  |77

 27  |Guh |97 |F  |20
 28  |Guh |97 |F  |28
 29  |Guh |97 |F  |28
 30  |Guh |97 |F  |23

我的目标是让查询产生无重复的pack_id 类似的东西：

|tid |name|age|sex|pack_id
 1   |Joe |57 |M  |77    
 3   |Joe |57 |M  |89
 5   |Joe |57 |M  |94

 6   |Roy |98 |M  |7
 7   |Roy |98 |M  |8
 8   |Roy |98 |M  |9

 12  |Joe |46 |M  |96

 13  |Guh |97 |F  |1

 14  |Kin |68 |F  |33
 18  |Kin |68 |F  |35
 19  |Kin |68 |F  |37

 20  |Pit |43 |F  |77
 21  |Pit |43 |F  |1
 22  |Pit |43 |F  |2

 25  |Joe |71 |M  |75

 26  |Bob |82 |M  |77

 27  |Guh |97 |F  |20
 28  |Guh |97 |F  |28

 30  |Guh |97 |F  |23

我试过了：

SELECT `tid` ,`name`,`age`,`sex`,`pack_id` FROM `myTable` group by `pack_id` //FAILED

试过这个以及：

SELECT DISTINCT(`pack_id`) ,`name`,`age`,`sex`,`pack_id` FROM `myTable` group by `pack_id`// RETURNS ONE SINGLE 'name' MANY TIMES

尝试

MySQL select distinct where in all

尝试

How can i get all the unique id having more than one id with different address

尝试了更多......

仍然做不到。

Answer 1

听起来你需要GROUP BY两个级别：name和pack_id。例如：

SELECT tid,name,age,sex,pack_id FROM yourtable GROUP BY name, pack_id;

有关更多详情，请参阅reference manual

Answer 2

SELECT min(tid), name,age,sex,pack_id 
FROM myTable 
group by name, age, sex, pack_id

在MySql中，SELECT all with DIFFERENT id？

2 个答案: