Question

我想从表USERS中获得一个列表，它给了我所有具有相同COMPANYID但地址1或地址2不匹配的USERS。

| userID| COMPANYID| ADDRESS 1    | ADDRESS 2
|     3 | B        | Street B     | 12
|     4 | B        | Street B     | 13
|     5 | C        | Street C     | 14
|     6 | C        | Street C     | 14
|     7 | C        | Street C     | 15

我想获得COMPANYID存在多次的所有行，但公司用户之间的地址不匹配。这就是我想要的：

SELECT *FROM USERS WHERE comapnyID IN (SELECT companyID FROM USERS GROUP BY companyID HAVING COUNT(*)>1) ORDER BY companyID

我可以通过查询获得第一部分：

gsutil mv

但我不想包含地址已匹配的那些。

Answer 1

很难：）

select * from USERS where companyid in (
    select t1.companyid  from (
        SELECT n.companyid,n.address1,n.address2,
            CASE WHEN n.address1=o.address1 AND n.address2=o.address2 THEN "No Change"
            ELSE "Changed"
            END as ChangeFlag
        FROM USERS n
        LEFT OUTER JOIN USERS o ON n.companyid=o.companyid
        ) t1
    where ChangeFlag="Changed")
 order by 1,2

Answer 2

尝试以下查询

SELECT * FROM USERS WHERE comapnyID IN (SELECT COUNT(companyID) FROM USERS GROUP BY companyID HAVING COUNT(companyID)>1) group by comapnyID ORDER BY companyID

Answer 3

尝试此查询

SELECT 
    A.*
FROM
    USERS AS A
        JOIN
    USERS AS B ON A.COMPANYID = B.COMPANYID
       and A.userId = B.userId
        AND A.ADDRESS2 <> B.ADDRESS2
        AND A.ADDRESS1 <> B.ADDRESS1

Answer 4

SELECT T.* FROM
USERS T
INNER JOIN
(
  SELECT DISTINCT T1.COMPANYID FROM
  (
    SELECT COMPANYID,COUNT(*) AS CADDRESS2 
    FROM USERS 
    WHERE COMPANYID IN (SELECT COMPANYID FROM USERS GROUP BY COMPANYID HAVING COUNT(*)>1) 
    GROUP BY COMPANYID
  ) AS T1
    INNER JOIN
  (
    SELECT COMPANYID,COUNT(*) CADDRESS2 
    FROM USERS 
    WHERE COMPANYID IN (SELECT COMPANYID FROM USERS GROUP BY COMPANYID HAVING COUNT(*)>1) 
    GROUP BY COMPANYID,ADDRESS2
  ) AS T2
  ON T1.COMPANYID = T2.COMPANYID
  AND T1.CADDRESS2 != T2.CADDRESS2
) AS T4
ON T.COMPANYID = T4.COMPANYID

<强>输出

USER    COMPANYID   ADDRESS1    ADDRESS2
3       B           Street B    12
4       B           Street B    13
5       C           Street C    14
6       C           Street C    14
7       C           Street C    15

现场演示

http://sqlfiddle.com/#!9/9a153b/35

Answer 5

这个应该有效：

SELECT * FROM USERS WHERE COMPANYID IN（SELECT COMPANYID FROM USERS WHERE userID！= 0 GROUP BY COMPANYID有COUNT（）＆gt; 1）和COMPANYID不在（ SELECT COMPANYID FROM USERS GROUP BY COMPANYID，address1，address2有COUNT（）＆gt; 1）ORDER BY COMPANYID

选择具有相同ID但值不同的行

5 个答案: