我想选择具有不同行但ID相同的数据。
| Codenum | Letter | description |
| 001 | A | APPLES |
| 002 | A | BANANA |
| 001 | B | RED |
| 001 | B | GREEN |
| 002 | B | BLUE |
| 002 | B | YELLOW |
我想要的是获得分类为LETTER B的行,还有使用相同Codenum的LETTER A的描述。
不完整的查询是SELECT description FROM table where letter = B
,我想添加与Codenum对应的字母A的描述
期望的结果:
001 B RED APPLES
001 B GREEN APPLES
002 B BLUE BANANA
002 B YELLOW BANANA
提前多多感谢
答案 0 :(得分:1)
您可以使用子选择来执行此操作:
SELECT Codenum, Letter, description, (SELECT description FROM mytable x where x.Codenum = second.Codenum AND Letter = 'A') AS adescription
FROM mytable second
WHERE mytable.Letter = 'B'
答案 1 :(得分:0)
试试这个
select a.codenum, a.letter, a.description, b.description
from table a join table b
on b.codenum = a.codenum
and b.letter = 'A'
where a.letter = 'B'
答案 2 :(得分:0)
我认为你要找的是group_concat()
尝试此查询:
SELECT
GROUP_CONCAT(`description`) as description_concat
FROM
`table_name`
WHERE
`letter` = 'B'
GROUP BY
`letter`
答案 3 :(得分:0)
确切查询:
select a.codenum, a.letter, a.description,b.description
from tbl_data a join tbl_data b on b.codenum = a.codenum
and b.letter = 'A' where a.letter = 'B'