“堆叠”块？

Question

是否可以在另一个块中调用块？

例如：

-(void)doSomethingWithBlock:(void (^)(id))parameterBlock{

     Blah * object = [Blah doThisblock:^(id sender) {

     //invoke "parameterBlock" here..

     // do other things after as well..

     }
 }

如果可能的话，我该怎么做呢？

Answer 1

我发现我可以通过这样做来调用块：

    -(void)doSomethingWithBlock:(void (^)(id))parameterBlock{

            Blah * object = [Blah doThisblock:^(id sender) {

                   parameterBlock();

                   // do other things after as well..

           }
     }