Question

我有一个父模型和子模型。

我想强制要求在创建新父项时至少创建一个子项。

我使用的是nested_form gem，目前正在使用此脚本来限制每条记录添加的子项数。

$(function() {
var fieldsCount,
  maxFieldsCount = 4,
  $addLink = $('a.add_nested_fields');

function toggleAddLink() {
$addLink.toggle(fieldsCount <= maxFieldsCount)
}

$(document).on('nested:fieldAdded', function() {
fieldsCount += 1;
toggleAddLink();
});

$(document).on('nested:fieldRemoved', function() {
fieldsCount -= 1;
toggleAddLink();
});  

// count existing nested fields after page was loaded
fieldsCount = $('form .fields').length;
toggleAddLink();
})

我还有办法包括一个＆＃34;最小值＆＃34;需求？让我们说（1）孩子？基本上删除＆＃34;删除链接＆＃34;如果只有（1）嵌套形式可见。

Answer 1

以下是我通过根据计数删除“删除”链接确定至少显示一个字段的代码

  $(function() {
  var fieldsCount,
  maxFieldsCount = 2,
  $addLink = $('a.add_nested_fields');

  var mfieldsCount,
  minFieldsCount = 0, // placed at 0 because first object is auto built from controller
  $removeLink = $('a.remove_nested_fields');

  function toggleAddLink() {
  $addLink.toggle(fieldsCount <= maxFieldsCount)
 }

  function toggleRemoveLink() {
  $removeLink.toggle(mfieldsCount <= minFieldsCount)
  }

  $(document).on('nested:fieldAdded', function() {
  fieldsCount += 1;
  toggleAddLink();
 });

 $(document).on('nested:fieldRemoved', function() {
 fieldsCount -= 1;
 toggleAddLink();
});

 $(document).on('nested:fieldRemoved', function() {
mfieldsCount -= 0;
toggleRemoveLink();
 });  

 // count existing nested fields after page was loaded
 fieldsCount = $('form .fields').length;
 toggleAddLink();

  mfieldsCount = $('form .fields').length;
  toggleRemoveLink();
 })

Answer 2

您可以在父级的控制器中调用构建方法new action。因此，当您转到父/新时，您将创建一个孩子。就是这样： @ parent.children.build

限制嵌套字段的最小计数

2 个答案: