Question

我正在进行日/夜循环，并且在Time.time上有lerp，因为如果我使用Time.deltaTime，它会在晚上12点左右转，所以当天早上12点。不过我离题了。我现在遇到的问题是，在任何时间设置下，它都会使lerp成为瞬间而不是 - 好吧......'lerp'。有什么想法解决这个问题？我是C＃newbie

我使用它作为时间脚本：

using UnityEngine;
using System.Collections;

public class timeFlow : MonoBehaviour 
{

public float Hours = 00;
public float Minutes = 00;

void Update()
{
if(Hours <= 23){

    if(Minutes >= 60)
    {
        Minutes = 0;
        if(Minutes <= 59)
        {
            Hours++;
        }
        else
        {
            Minutes = 0;
            Hours = 0;
            guiText.text = Hours.ToString("f0") + ":0" +    Minutes.ToString("f0");
        }
    }
    else
    {
        Minutes += UnityEngine.Time.deltaTime * 100;
    }

    if(Mathf.Round(Minutes) <= 9)
    {
        guiText.text = Hours.ToString("f0") + ":0" +    Minutes.ToString("f0");
    }
    else
    {
        guiText.text = Hours.ToString("f0") + ":" + Minutes.ToString("f0");
    }
}

else {
    Hours = 0;
    }
}
}

这是lerp脚本：

using UnityEngine;
using System.Collections;

public class cycleFlow : MonoBehaviour {

public Color32 night = new Color32(30, 30, 30, 255);
public Color32 day = new Color32(255, 255, 255, 255);

public GameObject Timer;
private timeFlow TimeFlow;

void Awake () {

    TimeFlow = Timer.GetComponent<timeFlow> ();

}

void Update () {
    DayNightCycle ();
}

void DayNightCycle()
{

    foreach (SpriteRenderer child in    transform.GetComponentsInChildren<SpriteRenderer>()) {
        if (TimeFlow.Hours == 18){
            child.color = Color.Lerp(day, night, Time.time);
        }

        if (TimeFlow.Hours == 6) {
            child.color = Color.Lerp(night, day, Time.time);
        }
    }
}
}

Answer 1

你可以写这样的东西，Lerp取实际（从）值，最终（到）值和分数值。（此处Time.deltaTime）现在，当您的计时器到达18小时时，您的颜色将在几个更新函数调用中更改为夜晚的颜色（您可以通过乘以Time.deltaTime来控制更改时间）：）

foreach ( SpriteRenderer child in transform.GetComponentsInChildren<SpriteRenderer>() ) {
    if ( TimeFlow.Hours == 18 ) {
        child.color = Color.Lerp(child.color, night, Time.deltaTime);
        // here two times faster
        // child.color = Color.Lerp(child.color, night, Time.deltaTime * 2.0f);
    }

    if ( TimeFlow.Hours == 6 ) {
        child.color = Color.Lerp(child.color, day, Time.deltaTime);
        // here half slower :)
        // child.color = Color.Lerp(child.color, night, Time.deltaTime * 0.5f);
    }
}

Answer 2

与时间一起使用时，我很难理解lerp。也许这个例子可以帮助某人：

// lerp values between 0 and 10 in a duration of 3 seconds:
private float minValue = 0.0f;
private float maxValue = 10.0f;

private float totalDuration = 3.0f; 
private float timePassed = 0.0f;

private float currentValue;

void Update()
{
    timePassed += Time.deltaTime;

    // Lerp expects a value between 0 and 1 as the third parameter,
    // so we need to divide by the duration:
    currentValue = Mathf.Lerp(minValue, maxValue, timePassed/totalDuration);
}

注意：您需要为：

添加一些逻辑

处理何时开始/停止lerping
何时重置timePassed

Time.time使我的Color Lerp不'lerp'

2 个答案: