我的问题是我希望表单在增加时仍显示数据,但表单被阻止,我无法用它做任何事情。 这是我的代码:
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
while (true)
for (int i = 1; i < 11; i++)
richTextBox1.Text += "here" + i + "/n";
}
}
}
如何阻止表单阻止?
答案 0 :(得分:1)
private void Form1_Load(object sender, EventArgs e)
{
BackgroundWorker BWorker = new BackgroundWorker();
BWorker.DoWork += BWorker_DoWork;
BWorker.RunWorkerAsync();
}
void BWorker_DoWork(object sender, DoWorkEventArgs e)
{
// while(true) is meaningless.
for (int i = 1; i < 11; i++)
{
Action UpdateUI = () => { richTextBox1.Text += "here" + i + "/n"; };
this.BeginInvoke(UpdateUI);
}
}
答案 1 :(得分:0)
使用计时器
将您的工作周期分成几个步骤 private int _workStep;
private void button1_Click(object sender, EventArgs e)
{
_workStep = 0;
timerWork.Start();
}
private void timerWork_Tick(...)
{
switch(workStep)
{
case 0:
... // do something
if(something)
_workStep = 1;
case laststep:
timerWork.Stop();
}
}
或将工作放入线程(使用Thread
,BackgroundWorker
或Task
),但在更新内容时必须使用Invoke
/ BeginInvoke
用户界面(访问控件)。
答案 2 :(得分:0)
您可以这样做以获得响应式ui
delegate void DisplayInvoker(string text);
private void DisplayinRichTextbox(string text)
{
if (this.InvokeRequired)
this.BeginInvoke(new DisplayInvoker(DisplayinRichTextbox), text);
return;
}
richTextBox1.Text += text;
}
private void button1_Click(object sender, EventArgs e)
{
// some synchronization would have to be done kill old
// pool threads when the button is hit again
//
ThreadPool.QueueUserWorkItem((x) =>
{
while (true)
for (int i = 1; i < 11; i++)
DisplayinRichTextbox("here" + i + "/n");
});
}