Question

所以我试着编写一个函数，让我们称之为foo，它采用二进制图像的路径，沿着它获取Hough线，然后返回按照霍夫沿着多少个白色像素排序的线条线。这是我到目前为止的代码，但它在＆＃34; if（图像[（x1 +（i stepx）），（y1 +（i stepy））]。any（））崩溃：＆＃34;带有无效索引的行。你们看到我能做些什么来解决这个bug或者知道OpenCV中内置的功能来做我想做的事情吗？

def lineParams(line, length):
    (dist, angl) = line
    a = math.cos(angl)
    b = math.sin(angl)
    x0 = a * dist
    y0 = b * dist
    pt1 = (int(x0 - length * b), int(y0 + length * a))
    pt2 = (int(x0 + length * b), int(y0 - length * a))
    return (pt1, pt2)

def lineWhiteness(line, image):
    (pt1, pt2) = lineParams(line, len(image))
    count = 0
    (x1, y1) = pt1
    (x2, y2) = pt2
    stepx = (x2 - x1) / 100
    stepy = (y2 - y1) / 100
    for i in xrange(1, 100):
        #print image[(x1 + i * stepx), (y1 + i * stepy)]
        if(image[(x1 + (i * stepx)), (y1 + (i * stepy))].any()):
            count = count + 1
    return count

def foo(path, display):
    edges = CannyEdge(path, False)
    lines = cv2.HoughLines(edges, rho, theta, threshold)
    image = cv2.imread(path)
    lines = lines[0]
    lines = sorted(lines, key=lambda l: lineWhiteness(l, image))
    return lines

Answer 1

我最后通过使用OpenCV的行迭代器来解决它，如下所示，我正在尝试重写我的行参数函数以便更好。

def lineWhiteness(line, image):
    (pt1, pt2) = lineParams(line, len(image))
    count = 0
    li = cv.InitLineIterator(cv.fromarray(image), pt1, pt2)
    for (r, g, b) in li:
        if (r or g or b):
            count += 1
    return count

计算OpenCV中沿线的白色像素数

1 个答案: