Question

我的代码有问题！当我使用{“T，Q，J，K，A”}的组合输入5张牌时，它不会计算得分，而是跳到“你想再玩一次”。我相信它的逻辑错误但似乎无法找到它！任何人都可以帮我解决这个挑战吗？

#include <iostream>
using namespace std;
int main()
{
    int cardnum, total=0, aceCount=0, i; 
    char face, ans;
    do
    {
    total = 0;
    cout << "How many Cards Do you have in your hands? (Between 2 and 5):\n";
    cin >> cardnum;
    if(cardnum <2 || cardnum > 5)
       {
          cout << "Not a Valid number of cards!\n";
       }
    cout << "Please enter Your Card Values.(2-9 or T, J,Q,K, A): \n";
    for(i=0; i<cardnum; i++)
       {
          cin >> face;
          switch (face)
          {
             case '2' :
                  total+=2;
                  break;
             case '3' :
                  total+=3;
                  break;
             case '4' :
                  total+=4;
                  break;
             case '5' :
                  total+=5;
                  break;
             case '6' :
                  total+=6;
                  break;  
             case '7' :
                  total+=7;
                  break;
             case '8' :
                  total+=8;
                  break;
             case '9' :
                  total+=9;
                  break;
             case 't' :
             case 'j' :
             case 'q' :
             case 'k' :
             case 'T' :
             case 'J' :
             case 'Q' :
             case 'K' :
                  total+=10;
                  break;
             case 'A' :
             case 'a' :
                  total+=11;
                  aceCount++;
          }
      }
      if(total <=21)
      {
         cout << "Your Total Score is: " << total<<endl;
      }
      else if(aceCount > 0 && total > 21)
      {
         do
         {
            total-=10;
            aceCount--;
         }while (aceCount > 0 && total >21);

         if(total <=21)
        {
            cout << "Your Total Score is: " << total<<endl;
        }
      }
         else if(total > 21)
        {
            cout << "Your Total Score is: " << total<< " Which Means You Busted!\n";
        }

    cout << "Do You Wish to Calculate Your Score Again? (Type y OR Y).\n";
    cin >> ans;
    }while(ans == 'y' || ans=='Y');    

    cout << "GOOD BYE! Play NEXT TIME!\n";
    system("PAUSE");
    return 0;
}

Answer 1

if(total <=21)
{
    cout << "Your Total Score is: " << total<<endl;
}

你在两条线上都有这个，所以你的其他所需条件都没有得到满足。只需将其第二次迭代更改为：

if(total > 21)
{
    cout << "Your Total Score is: " << total<<endl;
}

Answer 2

修复缩进，使问题更加明显。

当您在第一个else块中输入ace处理代码时，将不会执行第三个else块。所以只有在＆lt; = 21时才打印得分。你应该在处理完Aces后进行打印，这两个块应该是相互独立的。

未经测试，但代码应如下所示：

  if(aceCount > 0 && total > 21)
  {
     do
     {
        total-=10;
        aceCount--;
     }while (aceCount > 0 && total >21);
  }

  if(total <=21)
        cout << "Your Total Score is: " << total<<endl;
  }
  else if(total > 21)
  {
        cout << "Your Total Score is: " << total<< " Which Means You Busted!\n";
  }

BlackJack评分程序有错误

2 个答案: