Question

我有一个包含一些信息和时间示例的表

+----+-------------------+
| ID |     DateTime      |
+----+-------------------+
| 1  | 10/1/2014 10:10AM |
| 2  | 10/1/2014 11:00AM |
| 3  | 10/1/2014 12:00AM |
| 4  | 10/1/2014 14:10AM |
| 1  | 10/1/2014 02:30AM |
| 2  | 10/1/2014 10:10AM |
| 1  | 10/1/2014 10:40AM |
+----+-------------------+

我想像这样进行计数选择

from 10:00 to 11:00  ID 1  2 counts    ID 2    1 count
from 11:00 to 12:00  ID 3  1 count
from 14:00 to 15:00  ID 4  1 count
from 02:00 to 03:00  ID 1  1 count

所以我想每小时对搜索进行分组，并在每小时内计算每个ID 我如何在oracle select statment中执行此操作

Answer 1

我将使用三个步骤：

提取小时部分;您可以使用TRUNC(..., 'HH')
使用GROUP BY计算个人计数，小时和ID
转动这些结果（使用内置PIVOT功能或使用GROUP BY / SUM）

总而言之（使用GROUP BY和SUM）：

with v_data as (
  select 1 as id, to_date('2014-01-10 10:10:00', 'YYYY-MM-DD hh24:mi:ss') as datetime from dual union all
  select 2 as id, to_date('2014-01-10 11:00:00', 'YYYY-MM-DD hh24:mi:ss') as datetime from dual union all
  select 3 as id, to_date('2014-01-10 12:00:00', 'YYYY-MM-DD hh24:mi:ss') as datetime from dual union all
  select 4 as id, to_date('2014-01-10 14:10:00', 'YYYY-MM-DD hh24:mi:ss') as datetime from dual union all
  select 1 as id, to_date('2014-01-10 02:30:00', 'YYYY-MM-DD hh24:mi:ss') as datetime from dual union all
  select 2 as id, to_date('2014-01-10 10:10:00', 'YYYY-MM-DD hh24:mi:ss') as datetime from dual union all
  select 1 as id, to_date('2014-01-10 10:40:00', 'YYYY-MM-DD hh24:mi:ss') as datetime from dual 
) 
select hour, 
  sum(case when id = 1 then cnt else 0 end) as id1,
  sum(case when id = 2 then cnt else 0 end) as id2,
  sum(case when id = 3 then cnt else 0 end) as id3,
  sum(case when id = 4 then cnt else 0 end) as id4
from (  
  select 
    id, hour, count(*) as cnt 
  from (
    select 
      d.*, 
      trunc(datetime, 'HH') as hour
    from v_data d
  )
  group by id, hour
) 
group by hour
order by hour

仅当ID列表修复时才有效 - 如果需要动态ID列表，则必须使用动态SQL。

Oracle根据每个时间段在时间和组计数之间进行选择

1 个答案: