如何选择计数（*）分组并同时选择*？

Question

例如，我有桌子：

ID   |   Value
1         hi
1         yo
2         foo
2         bar
2         hehe
3         ha
6         gaga

我希望我的查询获取ID，Value;同时，返回的集合应该按每个ID的频率计数顺序排列。

我尝试了下面的查询，但不知道如何同时获取ID和值列：

SELECT COUNT(*) FROM TABLE group by ID order by COUNT(*) desc;

计数对我来说无关紧要，我只需要数据按此顺序排列。

欲望结果：

ID   |   Value

2         foo
2         bar
2         hehe
1         hi
1         yo
3         ha
6         gaga

As you can see because ID:2 appears most times(3 times), it's first on the list, 
then ID:1(2 times) etc. 

Answer 1

像

这样的东西

SELECT  t.ID,
        t.Value,
        c.Cnt
FROM    TABLE t INNER JOIN
        (
            SELECT  ID,
                    COUNT(*) Cnt
            FROM    TABLE
            GROUP BY ID
        ) c ON  t.ID = c.ID
ORDER BY c.Cnt DESC

SQL Fiddle DEMO

Answer 2

select t.id, t.value
from TABLE t
inner join 
(
  SELECT id, count(*) as cnt 
  FROM TABLE 
  group by ID
)
x on x.id = t.id
order by x.cnt desc

Answer 3

你可以试试这个 -

    select id, value, count(*) over (partition by id)  freq_count
from
(
select 2  as ID,  'foo' as value
from dual
union all
select 2,         'bar'
from dual
union all
select 2,         'hehe'
from dual
union all
select 1 ,        'hi'
from dual
union all
select 1  ,       'yo'
from dual
union all
select 3   ,      'ha'
from dual
union all
select 6    ,     'gaga'
from dual
)
order by 3 desc;

Answer 4

我看到问题已经得到解答，但由于缺少最明显和最简单的解决方案，我无论如何都会发布它。它不使用自联接或子查询：

SQL> create table t (id,value)
  2  as
  3  select 1, 'hi' from dual union all
  4  select 1, 'yo' from dual union all
  5  select 2, 'foo' from dual union all
  6  select 2, 'bar' from dual union all
  7  select 2, 'hehe' from dual union all
  8  select 3, 'ha' from dual union all
  9  select 6, 'gaga' from dual
 10  /

Table created.

SQL> select id
  2       , value
  3    from t
  4   order by count(*) over (partition by id) desc
  5  /

        ID VALU
---------- ----
         2 bar
         2 hehe
         2 foo
         1 yo
         1 hi
         6 gaga
         3 ha

7 rows selected.