Question

示例 input1.json


[{
    "organizationId": "org1",
    "status": "UP",
    "server": "server1",
    "somekey1" : "somevalue1"
}, 
{
    "organizationId": "org1",
    "status": "DOWN",
    "server": "server2",
    "somekey2" : "somevalue2"
},
{
    "organizationId": "org1",
    "status": "DOWN",
    "server": "server3"
},
{
    "organizationId": "org2",
    "server": "server1",
    "status": "UP",
    "somekey2" : "somevalue2"
},
{
    "organizationId": "org2",
    "server": "server2",
    "status": "UP",
    "somekey4" : "somevalue4"
}]

预期 output.json


[{
        "organizationId": "org1",
        "server1": "UP",
        "server2": "DOWN",
        "server3": "DOWN",
        "Down_Count": 2,
        "somekey2" : "somevalue2"
    },
    {
        "organizationId": "org2",
        "server1": "UP",
        "server2": "UP",
        "Down_Count": 0,
       "somekey2" : "somevalue2"
    }]

输入是两个文件的数组对象。我的目标是

通过Down_Count分组来增加和填充新字段organizationId。我可以有多个具有相同organizationId的记录。因此，计数应该增加该状态DOWN的次数。
合并server和status字段。例如，"server":"server1", "status":"down"应该直接在最终输出中作为server1:down。我可以使用jq '.[] |= . + {(.server):.status}'
所有对象中都没有所有键。因此，我应该能够将我想要的键添加到最终输出中。让我们假设我知道要添加的密钥名称。在最终输出中，我只添加了"somekey2" : "somevalue2"

我发现使用jq cmd行处理器一起实现所有这些困难有些困难。有什么建议吗？

Answer 1

jq 解决方案：

jq 'group_by(.organizationId) 
    | map(reduce .[] as $o ({"Down_Count" : 0};
              if $o["status"] == "DOWN" then .Down_Count += 1 else . end
              | . + { ($o["server"]) : $o["status"],
                          "organizationId" : $o["organizationId"] }
          ))' input.json

输出：

[
  {
    "Down_Count": 2,
    "server1": "UP",
    "organizationId": "org1",
    "server2": "DOWN",
    "server3": "DOWN"
  },
  {
    "Down_Count": 0,
    "server1": "UP",
    "organizationId": "org2",
    "server2": "UP"
  }
]

Answer 2

这是您可以采取的另一种方法：

group_by(.organizationId) | map(
    reduce ([., [range(length)]] | transpose[]) as [$o,$i] (
        {
            organizationId: .[0].organizationId,
            Down_Count: (map(select(.status=="DOWN")) | length)
        };
        reduce $keys[] as $k (
            .["server\($i+1)"] = $o.status;
            if $o | has($k) then .[$k] = $o[$k] else . end
        )
    )
)

只需传入要复制的名为$keys的键数组。如果它存在于其中一个对象中，它将被复制到结果对象。

$ cat input.json
[{
    "organizationId": "org1",
    "status": "UP",
    "server": "server1",
    "somekey1" : "somevalue1"
}, 
{
    "organizationId": "org1",
    "status": "DOWN",
    "server": "server2",
    "somekey2" : "somevalue2"
},
{
    "organizationId": "org1",
    "status": "DOWN",
    "server": "server3"
},
{
    "organizationId": "org2",
    "server": "server1",
    "status": "UP",
    "somekey2" : "somevalue2"
},
{
    "organizationId": "org2",
    "server": "server2",
    "status": "UP",
    "somekey4" : "somevalue4"
}]

$ cat program.jq
group_by(.organizationId) | map(
    reduce ([., [range(length)]] | transpose[]) as [$o,$i] (
        {
            organizationId: .[0].organizationId,
            Down_Count: (map(select(.status=="DOWN")) | length)
        };
        reduce $keys[] as $k (
            .["server\($i+1)"] = $o.status;
            if $o | has($k) then .[$k] = $o[$k] else . end
        )
    )
)

$ jq --argjson keys '["somekey2"]' -f program.jq input.json
[
  {
    "organizationId": "org1",
    "Down_Count": 2,
    "server1": "UP",
    "server2": "DOWN",
    "somekey2": "somevalue2",
    "server3": "DOWN"
  },
  {
    "organizationId": "org2",
    "Down_Count": 0,
    "server1": "UP",
    "somekey2": "somevalue2",
    "server2": "UP"
  }
]

jq group by和Increment同时

2 个答案: