字典递归比较程序

时间:2014-01-29 06:08:40

标签: python dictionary

我创建了一个程序来比较两个python词典并输出两者的差异。它适用于深度为2或更小的字典。我该怎么做才能更深入地处理dicts,还有嵌套的dicts?

我遇到的另一个问题是,当我通过我的get_json()函数传递一个json数组时,它将作为列表返回。而且程序正在用列表而不是字典来查找。我该如何解决这个问题呢?

我的节目:

#!/usr/bin/env python2

import json

def get_json():
    file_name = raw_input("Enter name of JSON File: ")
    with open(file_name) as json_file:
        json_data = json.load(json_file)
        return json_data

def print_diff(json1, json2):
    for n in json1:
        if n not in json2:
            print('-   "' + str(n) + '":')
    for n in json2:
        if n not in json1:
            print('+   "' + str(n) + '":')
            continue
        if json2[n] != json1[n]:
            if type(json2[n]) not in (dict, list):
                print('-   "' + str(n) + '" : "' + str(json1[n]))
                print('+   "' + str(n) + '" : "' + str(json2[n]))
            else:
                if type(json2[n]) == dict:
                    print_diff(json1[n], json2[n])
                    continue
    return


def main():
    file1 = get_json()
    print(type(file1))
    file2 = get_json()
    print(type(file2))
    print_diff(file1, file2)

if __name__ == "__main__":
    main()

dict 1的例子:

{
    "widget": {
        "debug": "on",
        "window": {
            "title": "Sample Konfabulator Widget",
            "name": "main_window",
            "width": 500,
            "height": 500
        },
        "image": {
            "src": "Images/Sun.png",
            "name": "sun1",
            "hOffset": 250,
            "vOffset": 250,
            "alignment": "center"
        },
        "text": {
            "data": "Click Here",
            "size": 36,
            "style": "bold",
            "name": "text1",
            "hOffset": 250,
            "vOffset": 100,
            "alignment": "center",
            "onMouseUp": "sun1.opacity = (sun1.opacity / 100) * 90;"
        }
    }
}

dict 2的例子:

{
    "widget": {
        "debug": "on",
        "window": {
            "title": "Sample Konfabulator Widget",
            "name": "main_window",
            "width": 500,
            "height": 500
        },
        "image": {
            "src": "Images/Sun.png",
            "name": "sun2",
            "hOffset": 100,
            "vOffset": 100,
            "alignment": "center"
        },
        "text": {
            "data": "Click Here",
            "size": 36,
            "style": "bold",
            "name": "text1",
            "hOffset": 250,
            "vOffset": 100,
            "alignment": "center",
            "onMouseUp": "sun1.opacity = (sun1.opacity / 100) * 90;"
        }
    }
}

示例输出:

Enter name of JSON File: JSON1.json
<type 'dict'>
Enter name of JSON File: JSON2.json
<type 'dict'>
-   "vOffset" : "250
+   "vOffset" : "100
-   "name" : "sun1
+   "name" : "sun2
-   "hOffset" : "250
+   "hOffset" : "100

2 个答案:

答案 0 :(得分:2)

我编写了以下代码,可以比较两个不同深度的词典,并将差异打印到控制台输出。请注意,如果密钥在第一个字典中找到而在第二个字典中找不到,则只打印未找到的密钥(它不会在躺着的树下打印)。我希望这是预期的。此代码适用于单向比较,因此您需要进行两次调用以便以其他方式比较字典。

def findDiff(d1, d2, path=""):
    for k in d1.keys():
        if not d2.has_key(k):
            print path, ":"
            print k + " as key not in d2", "\n"
        else:
            if type(d1[k]) is dict:
                if path == "":
                    path = k
                else:
                    path = path + "->" + k
                findDiff(d1[k],d2[k], path)
            else:
                if d1[k] != d2[k]:
                    print path, ":"
                    print " - ", k," : ", d1[k]
                    print " + ", k," : ", d2[k] 

print "comparing s1 to s2:"
print findDiff(s1,s2)
print "comparing s2 to s1:"
print findDiff(s2,s1)

输出:

comparing s1 to s2:
widget->text :
data as key not in d2 
widget->text->window->image :
 -  vOffset  :  250
 +  vOffset  :  100
widget->text->window->image :
 -  name  :  sun1
 +  name  :  sun2
widget->text->window->image :
 -  hOffset  :  250
 +  hOffset  :  100
None
comparing s2 to s1:
widget->text->window->image :
 -  vOffset  :  100
 +  vOffset  :  250
widget->text->window->image :
 -  name  :  sun2
 +  name  :  sun1
widget->text->window->image :
 -  hOffset  :  100
 +  hOffset  :  250
None

请注意,在您的问题中,您没有考虑密钥是否有差异,密钥路径未打印。我在我的代码中打印它。我已从widget-&gt;文本中删除了数据元素以进行测试。所以,请忽略此控制台输出

答案 1 :(得分:0)

没有阅读你所有的东西,

def check_dict(first, second):
    for key in first:
        for keyTwo in second:

            if type(first[key]) == dict and type(second[keyTwo]) == dict:
                return check_dict(first[key], second[keyTwo])
            if not first[key] == second[keyTwo]:
                return false

目前没有python解释器的访问权限,但是这样做的事情应该有效。这只是一个想法的开始,但希望这是足以引发某些事情的信息。