Question

我有以下PHP代码：

<?php

class StackableAr extends Stackable{
    public function run(){}
}

class MyThread1 extends Thread{

    public $settings;

    public function __construct($settings){
        $this->settings = $settings;
    }

    public function run(){
        print "thread1: start\n";
        for($n = 0; $n < 8; $n++){
            print "thread1: $n\n";
            if($n == 2){
                print_r($this->settings);
            }
            elseif($n == 4){
                $this->settings['test2'] = new StackableAr();
                $this->settings['test2']['attr2'] = 'string2';
                $this->settings['test3'] = 'string3';
            }
            elseif($n == 6){
                print_r($this->settings);
            }
            sleep(1);
        }
        print "thread1: end\n";
    }
}

class MyThread2 extends Thread{

    public $settings;

    public function __construct($settings){
        $this->settings = $settings;
    }

    public function run(){
        print "thread2: start\n";
        for($n = 0; $n < 10; $n++){
            print "thread2: $n\n";
            if($n == 8){
                print_r($this->settings);
            }
            sleep(1);
        }
        print "thread2: end\n";
    }
}

$settings = new StackableAr();
$settings['test1'] = new StackableAr();
$settings['test1']['attr1'] = 'string1';

$myThread1 = new MyThread1($settings);
$myThread2 = new MyThread2($settings);

$myThread1->start();
$myThread2->start();

for($n = 0; $n < 12; $n++){
    print "main: $n\n";
    sleep(1);
}
?>

即使thread1不再存在，如何使$this->settings['test2']保持不变。我像pthread PHP example note那样说：你可以而且应该使用Stackable作为你希望传递给其他线程的所有数组的基础对象
thread1结束后$this->settings['test3']仍然存在。但为什么不$this->settings['test2']？

Answer 1

创建对象的上下文 - 这是对象真正存在的唯一位置 - 已经消失，因此对象被销毁。

其他数据从不依赖于创建它的上下文，因为它是一个简单的类型。

当您在线程周围传递对象时，只要共享对象，就必须确保存在创建上下文，对于主进程和该进程创建的所有线程都是如此。

进一步阅读：https://gist.github.com/krakjoe/6437782

在pthreads之间共享数组

1 个答案: