我正在使用代码进行三角测量的表面近似,这里复制了
[totalTris,three] = size(tri);
[totalPoints,two] = size(registeredPts);
% 1. Find the 3 equations for each vertex, and
% place them in c_equations matrix;
% c_equations = [A for vertex 1;
% A for vertex 2; ...
% A for vertex totalPoints]
% c(point,row,:) gives one row from an A matrix
Btotal = zeros(3,totalPoints);
c_equations = zeros(3*totalPoints,3,9);
for pointNum = 1:totalPoints
% B = [pixVal; x gradient; y gradient] at this vertex
z = pixelVals(pointNum);
B = [z; vGradientVecs(pointNum,1); vGradientVecs(pointNum,2)];
% Compile all B matrices into a vector
Btotal(:,pointNum) = B;
% B = Ac
x = registeredPts(pointNum,1);
y = registeredPts(pointNum,2);
A = [1 x y x^2 y^2 x^3 (x^2)*y x*(y^2) y^3; ...
0 1 0 2*x 0 3*(x^2) 2*x*y y^2 0; ...
0 0 1 0 2*y 0 x^2 2*x*y 3*(y^2)];
% Compile all A matrices into a vector
c_equations(pointNum,1,:) = A(1,:);
c_equations(pointNum,2,:) = A(2,:);
c_equations(pointNum,3,:) = A(3,:);
end
% 2. Find the c values for each triangle patch
c = zeros(totalTris,9);
c9 = zeros(9,9);
for triNum = 1:totalTris
p1 = tri(triNum,1);
p2 = tri(triNum,2);
p3 = tri(triNum,3);
B9 = [Btotal(:,p1); Btotal(:,p2); Btotal(:,p3)];
c9 = [c_equations(p1,1,:); c_equations(p1,2,:); c_equations(p1,3,:); ...
c_equations(p2,1,:); c_equations(p2,2,:); c_equations(p2,3,:); ...
c_equations(p3,1,:); c_equations(p3,2,:); c_equations(p3,3,:)];
c(triNum,:) = pinv(c9)*B9; %linsolve(c9,B9);
end
end
这是更大代码的一部分,当我运行代码时,它在MATLAB中给出了以下错误
Error using svd
Input must be 2-D.
Error in pinv (line 29)
[U,S,V] = svd(A,0);
Error in findBPolyCoefficients (line 50)
c(triNum,:) = pinv(c9)*B9;
根据我的搜索,我有正确的pinv语法,“输入必须是2D”错误超出了我的理解,如果任何人可以通过电话解决这个问题
答案 0 :(得分:2)
根据您提供的信息,c9
看起来是一个普通的3-D矩阵,即它的第二维是1。这些尺寸称为单体尺寸。 Squeeze
是用于折叠此类维度的命令。你应该这样做,
c9=squeeze(c9); %before doing pinv
这将使c9
为二维矩阵,然后可以计算其SVD。