Question

我有unix时间戳

$now         = strtotime("2013-12-10");
$start_date  = strtotime("2013-01-01");
$end_date    = strtotime("2013-12-31");

$start date和$end date跨越一段时间，$now时间戳位于两者的中间。

我也有一个可变日期间隔，如下所示：

$interval = new DateInterval('P1W');
// or
$interval = new DateInterval('P3D');

鉴于以上情况，我如何获得now所在区间的开始和结束时间戳？ $now，$start_date，$end_date和间隔将是动态的。

示例

假设我有这些参数：

$start_date = '2013-01-01 00:00:00';
$end_date   = '2013-12-31 23:59:59';
$now        = '2013-12-10 15:45:34';
$interval   = new DateInterval( 'P1W' );

我想知道$ now所处区间的开始和结束日期。我希望上述参数的输出是：

$int_start_date = '2013-12-10 00:00:00';
$int_end_date   = '2013-12-16 23:59:59';

Answer 1

我认为这比你的方法更简洁，更清洁。

$start_date    = new DateTime( '2013-01-01 00:00:00' );
$end_date      = new DateTime( '2013-12-31 23:59:59' );
$end_date_ts   = $end_date->getTimestamp();
$now           = new DateTime( '2013-12-10 15:45:34' );
$now_ts        = $now->getTimestamp();
$interval      = new DateInterval( 'P1W' );
$periods        = new DatePeriod( $start_date, $interval, $end_date );

/** @var \DateTime $period */
foreach($periods as $period){
    $periodEnd = clone $period;
    $periodEnd->add($interval);
    if($period < $now && $now < $periodEnd){
        $result = iterator_to_array(new \DatePeriod($period, $interval, $periodEnd->add($interval)));
        $int_start_date = $result[0];
        $int_end_date = $result[1];
        break;
    }
}

/** @var DateTime $int_start_date */
/** @var DateTime $int_end_date */
var_dump( $int_start_date->format( 'Y-m-d H:i:s' ) );
var_dump( $int_end_date->modify( '-1 Second' )->format( 'Y-m-d H:i:s' ) );

Answer 2

你可以尝试：

$now = time();
$interval = new DateInterval('P1W');

$interval_seconds = $interval->s + ($interval->i * 60) + ($interval->h * 60 * 60) + ($interval->d * 60 * 60 * 24);
$half_interval = round($interval_seconds / 2);

// Unix timestamps
$interval_start = $now - $half_interval;
$interval_end = $now + $half_interval;

编辑：继续发表评论后的第二个答案

这仅适用于长度为1的间隔 - 例如1周，1年等。

如果你的间隔是> 1然后你需要以某种方式确定你在这段时间内的距离......例如，对于2周的间隔，你是在第一周还是在第二周？

$now = time();

$interval = "week";

switch ($interval) {
    case "year":
        $start_int = strtotime(date("Y", $now)."-01-01 00:00:00");
        $end_int = strtotime(date("Y", $now)."-12-31 23:59:59");
    break;
    case "month":
        $start_int = strtotime(date("Y-m", $now)."-01 00:00:00");
        $end_int = strtotime(date("Y-m-t", $now)." 23:59:59");
    break;
    case "week":
        $start_week = date("Y-m-d", strtotime("previous Monday", $now));
        $end_week = date("Y-m-d", strtotime("next Sunday", $now));

        $start_int = strtotime($start_week." 00:00:00");
        $end_int = strtotime($end_week." 23:59:59");
    break;
    case "day":
        $start_int = strtotime(date("Y-m-d", $now)." 00:00:00");
        $end_int = strtotime(date("Y-m-d", $now)." 23:59:59");
    break;
    case "hour":
        $start_int = strtotime(date("Y-m-d H", $now).":00:00");
        $end_int = strtotime(date("Y-m-d H", $now).":59:59");
    break;
    case "minute":
        $start_int = strtotime(date("Y-m-d H:i", $now).":00");
        $end_int = strtotime(date("Y-m-d H:i", $now).":59");
    break;
}
echo date("Y-m-d H:i:s", $start_int), "<br>";
echo date("Y-m-d H:i:s", $end_int), "<br>";

更新3

我把你答案中的逻辑放到一个循环中：

$start_date    = new DateTime( '2013-01-01 00:00:00' );
$end_date      = new DateTime( '2013-12-31 23:59:59' );
$end_date_ts   = $end_date->getTimestamp();
$now           = new DateTime( '2013-12-10 15:45:34' );
$now_ts        = $now->getTimestamp();
$interval      = new DateInterval( 'P1W' );
$period        = new DatePeriod( $start_date, $interval, $end_date );

$int_start_date = $start_date;
$int_end_date   = $end_date;

foreach ( $period as $dt ) {
    $timestamp = $dt->getTimestamp();

    if ($now_ts >= $timestamp) {
        $int_start_date->setTimestamp($timestamp);
    }
    if ($now_ts < $timestamp and $timestamp < $int_end_date->getTimestamp()) {
        $int_end_date->setTimestamp($timestamp - 1);
    }
}
var_dump( $int_start_date->format( 'Y-m-d H:i:s' ) );
var_dump( $int_end_date->format( 'Y-m-d H:i:s' ) );

Answer 3

我自己已经解决了这个问题，但是很讨厌

$start_date    = new DateTime( '2013-01-01 00:00:00' );
$end_date      = new DateTime( '2013-12-31 23:59:59' );
$end_date_ts   = $end_date->getTimestamp();
$now           = new DateTime( '2013-12-10 15:45:34' );
$now_ts        = $now->getTimestamp();
$interval      = new DateInterval( 'P1W' );
$period        = new DatePeriod( $start_date, $interval, $end_date );

$intervals = array();

foreach ( $period as $dt ) {
    $intervals[] = $dt->getTimestamp();
}

$intervals[]    = $end_date_ts;
$int_start_date = new DateTime();
$int_end_date   = new DateTime();

for ( $i = 0; $i < count( $intervals ); $i++ ) {
    if ( $now_ts >= $intervals[$i] && $now_ts <= $intervals[$i+1]) {
        $int_start_date->setTimestamp($intervals[$i]);
        $int_end_date->setTimestamp($intervals[$i+1]-1);
            break;
    }
}

var_dump( $int_start_date->format( 'Y-m-d H:i:s' ) );
var_dump( $int_end_date->format( 'Y-m-d H:i:s' ) );

如果有人拥有它们，我很乐意接受更好的方法。

PHP - 获取当前日期间隔的开始和结束日期

3 个答案: