Question

这只是一个简单的水果捕捉游戏。

import pygame, random, time, os, webbrowser
from time import sleep
from pygame import* 
pygame.init()
myname=input('What is your name')

#set the window size
window= pygame.display.set_mode((800,600) ,0,24)
pygame.display.set_caption("Fruit Catch")

#game variables
gameover=pygame.image.load('gameover.jpg')
myscore=0
file = 'score.txt'
eating=pygame.mixer.Sound('data/eating.wav')
die=pygame.mixer.Sound('die.wav')
mylives=3
mouth_x=300
fruit_x=250
fruit_y=75
fruitlist=['broccoli.gif','chicken.gif']
keyclicks=0
#prepare for screen
myfont=pygame.font.SysFont("Britannic Bold", 55)
label1=myfont.render(myname, 1, (240, 0, 0))
label3=myfont.render(str(mylives), 1, (20, 255, 0))
#grapchics
fruit=pygame.image.load('data/chicken.png')
mouth=pygame.image.load('data/v.gif')
backGr=pygame.image.load('data/kfc.jpg')
backGr1=pygame.image.load('sj.jpg')
#endless loop

start=pygame.image.load('chibro.jpg')
end_it=False
while (end_it==False):
    window.blit(start, (0,0))
    myfont=pygame.font.SysFont("Impact", 55)
    label7=myfont.render("Welcome "+myname+" Click here to begin", 1, (255, 0, 0))
    myfont=pygame.font.SysFont("Impact", 30)
    label8=myfont.render("Catch as much Chicken and brocoli as you can", 1, (255, 0, 0))
    label9=myfont.render("If you miss 3, you will starve to death!", 1, (255, 0, 0))
    for event in pygame.event.get():
        if event.type==MOUSEBUTTONDOWN:
            end_it=True
    window.blit(label7,(10,500))
    window.blit(label8,(10,300))
    window.blit(label9,(10,400))
    pygame.display.update() 
running=True
while running:
    if fruit_y>=460:#check if at bottom, if so prepare new fruit
       fruit_x=random.randrange(50,530,1)
       fruit_y=75
       fruit=pygame.image.load('data/'+fruitlist[random.randrange(0,2,1)])
    else:fruit_y+=5

   #check collision
    if fruit_y>=456:
       mylives-=1
    if fruit_y>=440:
            if fruit_x>=mouth_x and fruit_x<=mouth_x+300 :
                    myscore+=1
                    fruit_y=600#move it off screen
                    eating.play()

    pygame.mouse.get_pressed() 
    for event in pygame.event.get():
            if (event.type==pygame.KEYDOWN):
                if (event.key==pygame.K_LEFT):
                        mouth_x-=55
                        keyclicks+=1
                if (event.key==pygame.K_RIGHT):
                        mouth_x+=55
                        keyclicks+=1 
            if event.type==MOUSEBUTTONDOWN and keyclicks>=2 :
                pygame.quit()
    label3=myfont.render(str(mylives), 1, (20, 255, 0))
    label2=myfont.render(str(myscore), 1, (20, 255, 0))
    text1='You caught'+str(myscore)
    text3='Press the mouse to close the game'
    label4=myfont.render(text1, 1, (135, 206, 250))
    myfont1=pygame.font.SysFont("Britannic Bold", 40)
    label5=myfont1.render(text3, 1, (255, 0, 0))

    if mylives==0:
       window.blit(gameover, (0,0))
       window.blit(label4, (500,400))
       die.play()
       pygame.time.get_ticks
       pygame.display.update()
       running=False
       webbrowser.open(file)

    else:

        window.blit(backGr,(0,0))
        window.blit(mouth, (mouth_x,440))
        window.blit(fruit,(fruit_x, fruit_y))
        window.blit(label1, (174, 537))
        window.blit(label2, (700, 157))
        window.blit(label3, (700, 400))
        window.blit(label5, (10, 0))
        pygame.display.update()

我如何做到这一点，当主循环开始并且运行为真时，计时器显示在屏幕上以秒计数，计时器在运行时结束为假任何想法的家伙？

Answer 1

我不确定在pygame中是否有内置方法，但这是我将如何做到的。

import time
在您进入游戏循环之前，请将您开始运行的时间存储为
startTime = time.time()这将被视为您的零时间。
创建一个新标签，每次更新时都会将str(time.time() - startTime)作为文本。你减去time.time（）这是当前时间，从零时间开始，得到自循环开始以来经过的时间，你有计时器。
如果要将其舍入为秒，则需要确保将时间值截断为int，否则它将是小数str(int(time.time() - startTime))

如果您正在寻找，请告诉我。

Answer 2

使用pygame.time.get_ticks()

完整示例 - 以毫秒为单位的时间，计时器以屏幕为中心，ESC - 退出，SPACE - 暂停计时器

编辑：现在显示分钟，秒，毫秒 - Python 2.x.对于Python 3.x，使用//代替/ counting_minutes，counting_seconds。

import pygame

pygame.init()

screen = pygame.display.set_mode( (800,600) )

font = pygame.font.SysFont(None, 32)

clock = pygame.time.Clock()

start_time = pygame.time.get_ticks() 

paused  = False
running = True
while running:

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False

        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_ESCAPE:
                running = False

            if event.key == pygame.K_SPACE:
                paused = not paused

    if not paused:
        counting_time = pygame.time.get_ticks() - start_time

        # change milliseconds into minutes, seconds, milliseconds
        counting_minutes = str(counting_time/60000).zfill(2)
        counting_seconds = str( (counting_time%60000)/1000 ).zfill(2)
        counting_millisecond = str(counting_time%1000).zfill(3)

        counting_string = "%s:%s:%s" % (counting_minutes, counting_seconds, counting_millisecond)

        counting_text = font.render(str(counting_string), 1, (255,255,255))
        counting_rect = counting_text.get_rect(center = screen.get_rect().center)

    screen.fill( (0,0,0) )
    screen.blit(counting_text, counting_rect)

    pygame.display.update()

    clock.tick(25)

如何在pygame中添加一个显示在屏幕上的运行计时器

2 个答案: