Question

import pygame, sys, pygame.mixer 

pygame.init()

size = width,height = 1256,640
screen = pygame.display.set_mode(size)
player_x = 0
player_y = 0
movex = 0

maintheme = pygame.mixer.Sound("music/mainthemes.ogg")
maintheme.play()

player_w = pygame.image.load("characters/player/character_w.png").convert_alpha()
player_a = pygame.image.load("characters/player/character_a.png").convert_alpha()
player_s = pygame.image.load("characters/player/character_s.png").convert_alpha()
player_d = pygame.image.load("characters/player/character_d.png").convert_alpha()

background1 = pygame.image.load("maps/background1.png").convert_alpha()

while True:

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()
        if event.type==KEYDOWN:
            if event.key==K_a:
                movex=-1

        screen.fill((0,0,0))
        screen.blit(background1,(0,0))
        screen.blit(player_s,(player_x,player_y))

        pygame.display.update()

错误是这样的：文件“/home/fenton/Desktop/main.py”，第27行，in if event.type == KEYDOWN： NameError：未定义名称“KEYDOWN” [以4.9秒完成]

Answer 1

你需要这样做：

if event.type==pygame.KEYDOWN:

否则，Python不知道定义KEYDOWN的位置。

此外，您可能希望将其更改为：

elif event.type==pygame.KEYDOWN:

因为event.type pygame.QUIT无法pygame.KEYDOWN。

Answer 2

from pygame.locals import *

添加此行，您就可以了。

然而，虽然这确实有效，但这是不好的做法，而且提供的解决方案 iCodez 应该受到青睐并改为使用。

Pygame KEYDOWN名称错误

2 个答案: