Math.IEEERemainder(x,y)是否相当于x%y?

时间:2009-12-28 21:29:28

标签: .net

Math.IEEERemainder(x,y) x%y 之间是否存在差异?

2 个答案:

答案 0 :(得分:12)

不,他们不等同。 MSDN显示了用于模数和IEEERemainder的不同公式,并有一个展示差异的简短示例程序:

IEEERemainder = dividend - (divisor * Math.Round(dividend / divisor))

Modulus = (Math.Abs(dividend) - (Math.Abs(divisor) * 
      (Math.Floor(Math.Abs(dividend) / Math.Abs(divisor))))) * 
      Math.Sign(dividend)

它们具有不同/相同输出的一些示例(取自MSDN):

                         IEEERemainder              Modulus
   3 / 2 =                          -1                    1
   4 / 2 =                           0                    0
   10 / 3 =                          1                    1
   11 / 3 =                         -1                    2
   27 / 4 =                         -1                    3
   28 / 5 =                         -2                    3
   17.8 / 4 =                      1.8                  1.8
   17.8 / 4.1 =                    1.4                  1.4
   -16.3 / 4.1 =    0.0999999999999979                   -4
   17.8 / -4.1 =                   1.4                  1.4
   -17.8 / -4.1 =                 -1.4                 -1.4

在类似问题上,通过六个变量也可以看到这个好answer

答案 1 :(得分:2)

不,他们不一样;请参阅documentation

这是来源:

    public static double IEEERemainder(double x, double y) { 
        double regularMod = x % y;
        if (Double.IsNaN(regularMod)) { 
            return Double.NaN;
        }
        if (regularMod == 0) {
            if (Double.IsNegative(x)) { 
                return Double.NegativeZero;
            } 
        } 
        double alternativeResult;
        alternativeResult = regularMod - (Math.Abs(y) * Math.Sign(x)); 
        if (Math.Abs(alternativeResult) == Math.Abs(regularMod)) {
            double divisionResult = x/y;
            double roundedResult = Math.Round(divisionResult);
            if (Math.Abs(roundedResult) > Math.Abs(divisionResult)) { 
                return alternativeResult;
            } 
            else { 
                return regularMod;
            } 
        }
        if (Math.Abs(alternativeResult) < Math.Abs(regularMod)) {
            return alternativeResult;
        } 
        else {
            return regularMod; 
        } 
    }