我有一个查询,它接受LINESTRING并将其转换为POINTS的结果集。
我无法弄清楚如何找到此结果集中2个特定行点之间的距离。
这是我到目前为止所做的:
DECLARE @GeographyToConvert geography
SET @GeographyToConvert = geography::STGeomFromText('LINESTRING (26.6434033 -81.7097817, 26.6435367 -81.709785, 26.6435783 -81.7098033, 26.6436067 -81.709825, 26.6435883 -81.709875, 26.64356 -81.7100417, 26.6434417 -81.710125, 26.6433167 -81.7101467, 26.643195 -81.7101033, 26.6431533 -81.7099517, 26.643175 -81.7097867, 26.643165 -81.7097917, 26.6431633 -81.7097367, 26.6431583 -81.7097083)',4326);
WITH GeographyPoints(N, Point) AS
(
SELECT 1, @GeographyToConvert.STPointN(1)
UNION ALL
SELECT N + 1, @GeographyToConvert.STPointN(N + 1)
FROM GeographyPoints GP
WHERE N < @GeographyToConvert.STNumPoints()
)
SELECT N,Point.STBuffer(0.25) as point, Point.STAsText() FROM GeographyPoints
例如,如何比较N = 10&amp;的距离? N = 11吗
这就是我的尝试,但它不起作用:
Declare @Point1 geography;
Declare @Point2 geography;
DECLARE @GeographyToConvert geography
--SET @GeometryToConvert = (select top 1 geotrack from dbo.SYNCTESTING2 where geotrack is not null);
SET @GeographyToConvert = geography::STGeomFromText('LINESTRING (26.6434033 -81.7097817, 26.6435367 -81.709785, 26.6435783 -81.7098033, 26.6436067 -81.709825, 26.6435883 -81.709875, 26.64356 -81.7100417, 26.6434417 -81.710125, 26.6433167 -81.7101467, 26.643195 -81.7101033, 26.6431533 -81.7099517, 26.643175 -81.7097867, 26.643165 -81.7097917, 26.6431633 -81.7097367, 26.6431583 -81.7097083)',4326);
WITH GeographyPoints(N, Point) AS
(
SELECT 1, @GeographyToConvert.STPointN(1)
UNION ALL
SELECT N + 1, @GeographyToConvert.STPointN(N + 1)
FROM GeographyPoints GP
WHERE N < @GeographyToConvert.STNumPoints()
)
SELECT N,Point.STBuffer(0.25) as point, Point.STAsText() FROM GeographyPoints
select @Point1 = Point FROM GeometryPoints where N = 10;
select @Point2 = Point FROM GeometryPoints where N = 11
select @Point1.STDistance(@Point2) as [Distance in Meters]
答案 0 :(得分:2)
这是你要找的吗?到上一点的距离?
DECLARE @GeographyToConvert geography
SET @GeographyToConvert = geography::STGeomFromText('LINESTRING (26.6434033 -81.7097817, 26.6435367 -81.709785, 26.6435783 -81.7098033, 26.6436067 -81.709825, 26.6435883 -81.709875, 26.64356 -81.7100417, 26.6434417 -81.710125, 26.6433167 -81.7101467, 26.643195 -81.7101033, 26.6431533 -81.7099517, 26.643175 -81.7097867, 26.643165 -81.7097917, 26.6431633 -81.7097367, 26.6431583 -81.7097083)',4326);
WITH GeographyPoints(N, Point, PreviousPoint, DistanceFromPrevious) AS
(
SELECT 1, @GeographyToConvert.STPointN(1), CAST(NULL AS GEOGRAPHY), CAST(0 AS Float)
UNION ALL
SELECT N + 1, @GeographyToConvert.STPointN(N + 1)
, @GeographyToConvert.STPointN(N)
, @GeographyToConvert.STPointN(N).STDistance(@GeographyToConvert.STPointN(N + 1))
FROM GeographyPoints GP
WHERE N < @GeographyToConvert.STNumPoints()
)
SELECT N,Point.STBuffer(0.25) as point, Point.STAsText(), PreviousPoint, DistanceFromPrevious FROM GeographyPoints
答案 1 :(得分:2)
替换
SELECT N,Point.STBuffer(0.25) as point, Point.STAsText() FROM GeographyPoints
用
SELECT * INTO #GeographyPoints FROM GeographyPoints
DECLARE @N1 INT = 10
DECLARE @N2 INT = 11
SELECT (SELECT Point FROM #GeographyPoints WHERE N=@N1).STDistance(
(SELECT Point FROM #GeographyPoints WHERE N=@N2))
DROP TABLE #GeographyPoints
只需更改@ N1&amp;的值@ N2作为必要