我有一个地图页面，其中包含一张Google地图和一张表格，用于计算数据库中两个选定点之间的距离，但我不知道如何使用PHP或AJAX和jQuery计算两个位置之间的距离。< / p>
我有一张包含以下内容的乡村表：
到目前为止，这是我的代码中的内容：
<?php require_once('include/connect.php'); ?>
<?php
session_start();
if(isset($_SESSION['login']) != 'true'){
header("location: index.php");
var_dump( $_SESSION['login']);
}
$login = ($_SESSION['login']);
$userid = ($_SESSION['user_id']);
$login_user = ($_SESSION['username']);
$fname = ($_SESSION['first_name']);
$lname = ($_SESSION['last_name']);
?>
<?php require_once('header.php'); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="keywords" content="" />
<meta name="description" content="" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Lam_El_Chamel</title>
<link href='http://fonts.googleapis.com/css?family=Oswald:400,300' rel='stylesheet' type='text/css' />
<link href='http://fonts.googleapis.com/css?family=Abel|Satisfy' rel='stylesheet' type='text/css' />
<link href="default.css" rel="stylesheet" type="text/css" media="all" />
<!--[if IE 6]>
<link href="default_ie6.css" rel="stylesheet" type="text/css" />
<![endif]-->
<script type = "text/javascript" src = "http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<style type="text/css">
body { font: normal 10pt Helvetica, Arial; }
#map { width: 850px; height: 500px; border: 0px; padding: 0px;left:0px;;}
#calculate-distance-form{position:absolute; top:600px; right:-120px; width:570px; height:200;}
</style>
<script src="http://maps.google.com/maps/api/js?key=AIzaSyAcdPXDgq5V8wmTiJedTBXGqIhzq8XdKdc&sensor=false" type="text/javascript"></script>
<script type="text/javascript">
var icon = new google.maps.MarkerImage("http://maps.google.com/mapfiles/ms/micons/blue.png",
new google.maps.Size(32, 32), new google.maps.Point(0, 0),
new google.maps.Point(16, 32));
var center = null;
var map = null;
var currentPopup;
var bounds = new google.maps.LatLngBounds();
function addMarker(lat, lng, info) {
var pt = new google.maps.LatLng(lat, lng);
bounds.extend(pt);
var marker = new google.maps.Marker({
position: pt,
icon: icon,
map: map
});
var popup = new google.maps.InfoWindow({
content: info,
maxWidth: 300
});
google.maps.event.addListener(marker, "click", function() {
if (currentPopup != null) {
currentPopup.close();
currentPopup = null;
}
popup.open(map, marker);
currentPopup = popup;
});
google.maps.event.addListener(popup, "closeclick", function() {
map.panTo(center);
currentPopup = null;
});
}
function initMap() {
map = new google.maps.Map(document.getElementById("map"), {
center: new google.maps.LatLng(0, 0),
zoom: 14,
mapTypeId: google.maps.MapTypeId.ROADMAP,
mapTypeControl: true,
mapTypeControlOptions: {
style: google.maps.MapTypeControlStyle.HORIZONTAL_BAR
},
navigationControl: true,
navigationControlOptions: {
style: google.maps.NavigationControlStyle.ZOOM_PAN
}
});
<?php
$query = mysql_query("SELECT * FROM location")or die(mysql_error());
while($row = mysql_fetch_array($query))
{
$name = $row['user_name'];
$lat = $row['lattitude'];
$lon = $row['longitude'];
//$desc = $row['desc'];
echo("addMarker($lat, $lon, '<b>$name</b><br />');\n");
}
?>
center = bounds.getCenter();
map.fitBounds(bounds);
}
</script>
<script type="text/javascript">
$(document).ready(function(){
$("select#location2").attr("disabled","disabled");
$("select#location1").change(function(){
id = $(this).val();
$("select#location2").attr("disabled","disabled");
$("select#location2").html("<option>wait...</option>");
$.post("select_location.php", {id:id}, function(data){
$("select#location2").removeAttr("disabled");
$("select#location2").html(data);
});
});
});
</script>
</head>
<body onload="initMap()" style="margin:0px; border:0px; padding:0px;">
<div id="wrapper">
<div id="page-wrapper">
<div id="page">
<div id="wide-content">
<h2>Map Border .....See Your Location with Google Map</h2>
<div id="map"></div>
<div id="calculate-distance-form">
<?php require_once('include/select.class.php'); ?>
<form action="calculate_distance.php" method="post">
Location one:
<select id="location1" name="pt1">
<?php echo $opt->Showlocation() ?>
</select><br />
<br />
Location two:
<select id="location2" name="pt2">
<option value="0">choose...</option>
</select><br />
<br />
<input type="submit" name="calculate" value="Calculate Distance" />
</form>
<!--
First Location<br />
<input type="text" name="lat1" placeholder="first Latitude" />
<input type="text" name="lon1" placeholder="first longitude"/><br />
Second Location<br />
<input type="text" name="lat2" placeholder="second latitude" />
<input type="text" name="lon2" placeholder="second longitude"/><br />
<input type="submit" name="calculate-distance" value="Calculate Distance" />
-->
</div>
</div>
</div>
</div>
</div>
<?php require_once('footer.php'); ?>
</body>
</html>
答案 0 :(得分：0)
假设您的公式如下：
<form action="calculate_distance.php" method="post">
<input type="text" name="lat1" placeholder="first Latitude" />
<input type="text" name="lng1" placeholder="first longitude"/><br />
<input type="text" name="lat2" placeholder="second latitude" />
<input type="text" name="lng2" placeholder="second longitude"/><br />
<input type="submit" name="calculate" value="Calculate Distance" />
</form>
您的calculate_distance.php脚本可能类似于此处提供的答案：Calc distance of two points in PHP。
...
<?php
$pi80 = M_PI / 180;
$lat1 = floatval($_POST['lat1']) * $pi80;
$lng1 = floatval($_POST['lng1']) * $pi80;
$lat2 = floatval($_POST['lat2']) * $pi80;
$lng2 = floatval($_POST['lng2']) * $pi80;
$r = 6372.797; // earth radius
$dlat = $lat2 - $lat1;
$dlng = $lng2 - $lng1;
$a = sin($dlat / 2) * sin($dlat / 2) + cos($lat1) * cos($lat2) * sin($dlng / 2) * sin($dlng / 2);
$c = 2 * atan2(sqrt($a), sqrt(1 - $a));
$km = $r * $c;
echo "Distance: ". $km;
?>
...