岩纸剪刀返回问题

时间:2013-10-23 03:45:44

标签: python

所以我遇到的问题是我的计数器在尝试将数字加起来时不断重置 我试图找出一种方法使计数器部分成为一个函数,但我无法弄清楚

winP1=0
winP2=0
tie=0

ans = input('Would you like to play ROCK, PAPER, SCISSORS?: ')

while ans == 'y':
    p1c = input('Player 1 enter either R,P, or S: ') #p1c stands for "player 1 choice"
    p2c = input('Player 2 enter either R,P, or S: ')
    ans = input('Would you like to play again: ')

def game(p1c,p2c):
    if p1c == p2c:                  #if its a tie we are going to add to the Tie variable
        return 0
    elif p1c == 'R' and p2c == 'P': #We will only set the Player 1 wins because
        return 1                    #player 2 wins can be set as else
    elif p1c == 'P' and p2c == 'S':
        return 1
    elif p1c == 'S' and p2c == 'R':
        return 1
    else:
        return -1

result = game(p1c,p2c)   
if result == -1:
    winP2 += 1
if result == 0:
    tie += 1
else:
    winP1 +=1

print('Player 1 won {} times. \nPlayer 2 won {} times. \nThere were {} ties.'.format(winP1,winP2,tie))

1 个答案:

答案 0 :(得分:3)

欢迎使用StackOverflow和Python编程!我希望你在这里过得愉快。

你的计数器一直在重置,因为在系统中你只玩一个游戏:

while ans == 'y':
    p1c = input('Player 1 enter either R,P, or S: ') #p1c stands for "player 1 choice"
    p2c = input('Player 2 enter either R,P, or S: ')
    ans = input('Would you like to play again: ')

我将在您的代码中移动一些东西,以获得您想要的结果,编辑最少,并希望这将向您展示您需要做什么。你走在正确的轨道上了!

我们将使用名为state的词典来跟踪游戏状态并传递它。

state = {
   'winP1':0,  
   'winP2':0,
   'tie':0
}

def game(p1c,p2c):
    if p1c == p2c:                  #if its a tie we are going to add to the Tie variable
        return 0
    elif p1c == 'R' and p2c == 'P': #We will only set the Player 1 wins because
        return 1                    #player 2 wins can be set as else
    elif p1c == 'P' and p2c == 'S':
        return 1
    elif p1c == 'S' and p2c == 'R':
        return 1
    else:
        return -1

def process_game(p1c, p2c, state): # Move this into a function
    result = game(p1c,p2c)   
    if result == -1:
        state['winP2'] += 1
    if result == 0:
        state['tie'] += 1
    else:
        state['winP1'] +=1

while ans == 'y':
    p1c = input('Player 1 enter either R,P, or S: ') #p1c stands for "player 1 choice"
    p2c = input('Player 2 enter either R,P, or S: ')
    process_game(p1c, p2c, state)
    ans = input('Would you like to play again: ')

print('Player 1 won {} times. \nPlayer 2 won {} times. \nThere were {} ties.'.format(state['winP1'],state['winP2'],state['tie']))