Question

我正在建造一个简单的石头剪刀游戏。它工作正常，除了当comp_count达到3时游戏不会停止的事实。我似乎无法理解为什么，因为它适用于player_count。请帮帮我！

from random import randint

player_count = 0
comp_count = 0

def game():
    player_choice = raw_input('Do you choose rock [r], paper [p], or scissors [s]? ')

    computer_choice = randint(0,2)
    #Rock = 0 Paper = 1 Scissors = 2

    #Player chooses paper, computer chooses rock
    if player_choice == "p" and computer_choice == 0:
        print 'Computer chose rock'
        player_won()

    #Player chooses rock, computer chooses scissors
    elif player_choice == 'r' and computer_choice == 2:
        print 'Computer chose scissors'
        player_won()

    #Player chooses scissors, computer chooses paper
    elif player_choice == 's' and computer_choice == 1:
        print 'Computer chose paper'
        player_won()

    #Computer chooses paper, player chooses rock
    elif player_choice == 'r' and computer_choice == 1:
        print 'Computer chose paper'
        computer_won()

    #Computer chooses rock, player chooses scissors
    elif player_choice == 's' and computer_choice == 0:
        print 'Computer chose rock'
        computer_won()

    #Computer chooses scissors, player chooses paper
    elif player_choice == 'p' and computer_choice == 2:
        print 'Computer chose scissors'
        computer_won()

    #Ties
    elif player_choice == 'r' and computer_choice == 0:
        print "It's a tie!"
        game()

    elif player_choice == 's' and computer_choice == 2:
        print "It's a tie!"
        game()

    elif player_choice == 'p' and computer_choice == 1:
        print "It's a tie!"
        game()

    #Wrong input
    else:
        print 'Please try again.'
        game()

def player_won():
    global player_count
    print 'You win!'
    player_count += 1
    print 'You have ' + str(player_count) + ' point(s).'
    while player_count < 3:
        game()

def computer_won():
    global comp_count
    print 'Computer wins!'
    comp_count += 1
    print 'Computer has ' + str(comp_count) + ' point(s).'
    while comp_count < 3:
        game()

print 'Welcome to Rock, Paper, Scissors! First to 3 points wins it all.'
game()

Answer 1

你的while循环是什么导致你的问题。只需在您的player_won和computer_won函数中更改为if，它就可以解决问题。

TIdTCPClient(OutboundClient).Host

现在去摇滚纸剪你的心！

Answer 2

我承认这不是你问题的直接答案，但我觉得有一种可能更简单的方式来写这个问题。

您可以让用户从输入中选择三个不同的数字而不是字母，或者只是将字母转换为数字。这样做的一个优点是，为了测试平局，你可以简单地写：

if player_choice == computer_choice:

即使检查游戏中谁赢了，如果它没有结合也不会非常困难，因为如果它全部是数字的，那么击败另一个的选项将是一个远离它的选项方向。因此，举例来说，你可以测试玩家是否赢了这样：

winning = computer_choice - 1
if winning == -1: winning = 2
if player_choice == wining:
    player_won()
else: #assuming we have already checked if it is a tie, we can say that otherwise the computer won.
    computer_won()

如果每个数字代表不同的选项（例如，如果你有一个词典链接0到摇滚，1到剪刀，2到纸张），那么这将检查用户是否在计算机之前选择了该选项，这将是获胜的选择。

这实际上可以让你通过相对较少的if语句检查谁赢了以及哪些选项。您的支票可能如下所示：

options = {0: "rock", 1:"scissors", 2:"paper"}

#collect player and computer choice here

print "computer chose "+options[computer_choice] #We will probably tell them what the computer chose no matter what the outcome, so might as well just put it once up here now that a variable can determine what the computer chose.

if player_choice == computer_choice:
    print "It's a tie!"
    game()

winning = computer_choice - 1
if winning == -1: winning = 2

if player_choice == wining:
    player_won()
else: #assuming we have already checked if it is a tie, we can say that otherwise the computer won.
    computer_won()

这对于使您的代码无效是非常必要的，但我认为如果您感兴趣，这将非常有用。

岩石纸剪刀AI问题

2 个答案: