我的小聊天客户端软件使用XML文件存储聊天记录,我的处理读/写的课程是:
public class History {
public String filePath;
public History(String filePath) {
this.filePath = filePath;
}
public String stripNonValidXMLCharacters(String in ) {
StringBuffer out = new StringBuffer(); // Used to hold the output.
char current; // Used to reference the current character.
if ( in == null || ("".equals( in ))) return ""; // vacancy test.
for (int i = 0; i < in .length(); i++) {
current = in .charAt(i); // NOTE: No IndexOutOfBoundsException caught here; it should not happen.
if ((current == 0x9) ||
(current == 0xA) ||
(current == 0xD) ||
((current >= 0x20) && (current <= 0xD7FF)) ||
((current >= 0xE000) && (current <= 0xFFFD)) ||
((current >= 0x10000) && (current <= 0x10FFFF)))
out.append(current);
}
return out.toString();
}
public synchronized void addMessage(String from, String agentName, String msg, String time, String channel) {
try {
DocumentBuilderFactory docFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docFactory.newDocumentBuilder();
org.w3c.dom.Document doc = docBuilder.parse(filePath);
Node data = doc.getFirstChild();
org.w3c.dom.Element root = doc.createElement(channel);
org.w3c.dom.Element message = doc.createElement("message");
org.w3c.dom.Element _sender = doc.createElement("sender");
_sender.setTextContent(stripNonValidXMLCharacters(from));
org.w3c.dom.Element _content = doc.createElement("content");
_content.setTextContent(stripNonValidXMLCharacters(msg));
org.w3c.dom.Element _recipient = doc.createElement("recipient");
_recipient.setTextContent(stripNonValidXMLCharacters(agentName));
org.w3c.dom.Element _time = doc.createElement("time");
_time.setTextContent(stripNonValidXMLCharacters(time));
message.appendChild(_sender);
message.appendChild(_content);
message.appendChild(_recipient);
message.appendChild(_time);
root.appendChild(message);
data.appendChild(root);
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
DOMSource source = new DOMSource(doc);
StreamResult result = new StreamResult(new File(filePath));
transformer.transform(source, result);
} catch (Exception ex) {
System.out.println(ex.getStackTrace());
// This is being trown randomly
}
}
public synchronized void getHistory(String channel) {
try {
File fXmlFile = new File(filePath);
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
org.w3c.dom.Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName(channel);
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
org.w3c.dom.Element eElement = (org.w3c.dom.Element) nNode;
if (getTagValue("sender", eElement).contains("Serv1")) {
printServerMsg(getTagValue("content", eElement).replace("%27", "'"), "", getTagValue("time", eElement));
} else {
printMsg(getTagValue("content", eElement).replace("%27", "'"), getTagValue("sender", eElement), getTagValue("time", eElement));
}
}
}
} catch (Exception ex) {
System.out.println("Filling Exception");
// This is also being trown
}
}
public String getTagValue(String sTag, org.w3c.dom.Element eElement) {
NodeList nlList = eElement.getElementsByTagName(sTag).item(0).getChildNodes();
Node nValue = (Node) nlList.item(0);
return nValue.getNodeValue();
}
}
写作时我遇到的例外情况是: `INVALID_CHARACTER_ERR:指定了无效或非法的XML字符.`
阅读例外Filling exception
这里的例外是java.lang.NullPointerException
任何想法我怎么能保证这不会发生?问题是这基本上打破了整个客户端
答案 0 :(得分:1)
而不是
System.out.println("Filling Exception");
总是使用
e.printStackTrace();
或者正确的日志框架,如log4j,并正确记录错误:
log.error("Filling Exception", e);
为什么这很重要?
因为通过这样做,您可以为我们提供完整的堆栈跟踪...
此外,为了转义字符串以用作XML内容,使用已经编写良好且经过验证的实用程序(如Apache commons StringEscapeUtils而不是重新发明轮子)是明智的
修改强>
来自OPs评论
哦,谢谢,我现在可以看到错误发生在getTagValue()
中
这里有NPE的多种可能性,但是杯线在这一行
NodeList nlList = eElement.getElementsByTagName(sTag).item(0).getChildNodes();
以下可以为null
eElement.getElementsByTagName(sTag).item(0)
如果文档中没有该名称的标记。
返回集合中的索引项。如果index大于或等于列表中的节点数,则此将返回null。
所以我会改写这样的方法:
public String getTagValue(String sTag, org.w3c.dom.Element eElement) {
Node n = eElement.getElementsByTagName(sTag).item(0);
if(e !=null) {
NodeList nlList = n.getChildNodes();
Node nValue = (Node) nlList.item(0);
if(nValue != null) {
return nValue.getNodeValue();
}
}
return ""; // or return null; if that is more applicable to the use case
}
另外要小心,现在这会返回一个空字符串,这可能会或可能不会很好:可以忽略所述节点不存在...