我需要动态地从xml文件中读取数据。我有70个标签名称来读取并以行的形式存储数据。通过查看上面的代码,我可以按需要读取数据,但是如何使用getTagValue(,)手动编写所有标记名,如何动态检索数据到getTagValue(,)。我发布了一些我在上面链接中尝试过的代码
public class ParseXML {
public static void main(String argv[]) {
try {
File fXmlFile = new File("data/Hotel.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
System.out.println(doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("staff");
System.out.println("-----------------------");
for (int i = 0; i < nList.getLength(); i++) {
Node nNode = nList.item(i);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
String firstname=getTagValue("firstname", eElement);
String lastName=getTagValue("lastname", eElement);
String nickname=getTagValue("nickname", eElement);
String salary=getTagValue("salary", eElement);
System.out.println(firstname+" ," + lastName+" ," + nickname+" ," + salary);
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
private static String getTagValue(String sTag, Element eElement) {
NodeList nlList = eElement.getElementsByTagName(sTag).item(0).getChildNodes();
Node nValue = (Node) nlList.item(0);
return nValue.getNodeValue();
}
}
答案 0 :(得分:0)
有没有办法动态生成标记名称到私有静态字符串getTagValue(String sTag, Element eElement)
"stag"
,而不是手动将"firstName","lastName","nickName","Salary"
声明为
String firstname=getTagValue("firstname", eElement);
String lastName=getTagValue("lastname", eElement);
String nickname=getTagValue("nickname", eElement);
String salary=getTagValue("salary", eElement);
听到我声明了4个TagNames,如果我有150个标签名称,那么它是真正的硬代码来手动编写150个TagNames。是否可以动态生成“stag”