Question

我想在散点图中绘制距平均值的距离散布。

这是我的代码：

import numpy as np
import matplotlib.pyplot as plt

x=[5,6,2,6,9]
y=[2,4,5,1,10]
x_mean=np.mean(x)
y_mean=np.mean(y)
x_dist_mean=x-x_mean
y_dist_mean=y-y_mean

my labels=['horse', 'cat' , 'dog', 'fish', 'ape']
plt.scatter(x_dist_mean, y_dist_mean ,alpha=0.5 )
plt.show()

但是，我想让散射点的大小与平均值的距离成比例，因此较大的距离会产生一个大的圆圈，而较小的距离会产生一个小圆圈。另外，我还想用my_labels中的标签名称为圆圈着色。

有人可以帮我这个吗？

Answer 1

只需传递s参数以获取点的大小，然后注释点。您可以更多地使用annotate功能。（我只是将标签放在点的中心，但你可以让它看起来不同......）

import numpy as np
import matplotlib.pyplot as plt

x=[5,6,2,6,9]
y=[2,4,5,1,10]
x_mean = np.mean(x)
y_mean = np.mean(y)
x_dist_mean = x - x_mean
y_dist_mean = y - y_mean

size = np.abs(x_dist_mean * y_dist_mean) * 100
labels=['horse', 'cat' , 'dog', 'fish', 'ape']

plt.scatter(x_dist_mean, y_dist_mean, s=size, alpha=0.5, label=labels)
for label, x, y in zip(labels, x_dist_mean, y_dist_mean):
    plt.annotate(label, xy = (x, y))

Matplotlib绘图散射，圆形大小从距离到平均值成比例

1 个答案: