Question

我有一个JFrame的程序，但当我使用我的“开始”动作时，它无法切换，而是它只是坚持运行而我需要强制关闭它:(你能说我吗？为什么，因为我是新手编码我不会发现我的错误是我的代码：

public class ClickBotSetUp extends JFrame  {

    static ClickBotSetUp frame;
    static Robot robot;

    public static void ClickBot() throws AWTException{
        final Robot robot = new Robot();

        robot.delay(2000);

        while(true)
        {
            {
                robot.mousePress(InputEvent.BUTTON1_MASK);
                robot.mouseRelease(InputEvent.BUTTON1_MASK);

                robot.delay(least);   
            }
        }
    }


public static void main(String[] args) throws IOException, AWTException {

        frame = new ClickBotSetUp("setup speed");
        frame.setVisible(true);
        frame.setBackground(Color.WHITE);

        robot = new Robot();
    }

//settings
static int least = 100;
JTextField count;
JButton start;
static int bot = 0;

public ClickBotSetUp(String title) throws HeadlessException
{
    super(title);

    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    setResizable(false);
    setSize(180, 145);

    Container cont = getContentPane();
    cont.setLayout(new BorderLayout());
    ((JComponent) cont).setBorder(BorderFactory.createEmptyBorder(15, 15,
            15, 15));

    //desing

    JLabel instructions = new JLabel("low nubers can crash");
    cont.add(instructions, BorderLayout.SOUTH);

    //buttons

    start = new JButton("start");
    start.setAction(starting);
    cont.add(start, BorderLayout.WEST);

    //score 

    JPanel scores = new JPanel();
    scores.setLayout(new BorderLayout());
    cont.add(scores, BorderLayout.CENTER);

    JPanel times = new JPanel();
    times.setLayout(new BorderLayout());
    scores.add(times, BorderLayout.WEST);

    //times

    count = new JTextField("100");
    count.setEditable(false);
    times.add(count, BorderLayout.CENTER);

    JButton add10 = new JButton("+10");
    add10.setAction(add_10);
    times.add(add10, BorderLayout.NORTH);

    JButton remove10 = new JButton("-10");
    remove10.setAction(remove_10);
    times.add(remove10, BorderLayout.SOUTH);
}

private AbstractAction starting = new AbstractAction("start") {

       @Override
          public void actionPerformed(ActionEvent arg0) {
          frame.setVisible(false);

          try {
            ClickBot();
        } catch (AWTException e) {

            e.printStackTrace();
        }

       }
};

private AbstractAction add_10 = new AbstractAction("+10") {

       @Override
          public void actionPerformed(ActionEvent arg0) {
        least = least + 10;
           count.setText("" +least+ "");
       }
};

private AbstractAction remove_10 = new AbstractAction("-10") {

       @Override
          public void actionPerformed(ActionEvent arg0) {

           if(least < 20){
           }else{
           least = least - 10;
           count.setText("" +least+ "");
           }

       }
};
}

Answer 1

while(true）是一个无限循环。它永远不会退出。

在while（someCondition Here）中有一些条件会破坏while循环。

同样@ArnaudDenoyelle指出

你需要一行

frame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);

这是因为X按钮的JFrame的默认行为等同于

frame.setDefaultCloseOperation(WindowConstants.HIDE_ON_CLOSE);

因此，大多数情况下，您需要在创建JFrame时手动添加行

Answer 2

while(true)将创建一个永无止境的循环。你应该使用一个标志，当条件满足时，应该改变标志，以便循环。

为什么我不能关闭这个程序？

2 个答案: