Question

我有一个名为Rack的抽象基类，我有不同类型的机架，它们是Rack的子机。我希望能够将通用C＃对象动态地转换为Rack类的不同子类，以便调用所有子进程作为方法的正确getData方法。这是我到目前为止所做的下面的代码调用Rack基类中的虚方法。我需要它来调用Rack的子类中的方法。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Reflection;

namespace IO_Interface
{
class Channel
{
    private object rack1;
    private object rack2;
    public Channel()
    {

    }

    public Channel(object h1, object h2)
    {
        rack1 = h1;
        rack2 = h2;
    }

    public void send()
    {

        Type rack1Info = rack1.GetType();
        Type rack2Info = rack2.GetType();
        string name = rack1.ToString();

        MethodInfo castMethod = rack1.GetType().GetMethod("getData").;
        castMethod.Invoke(rack1.GetType(), null);

    }

}
}`

Answer 1

您要做的是将rack1和rack2声明为Racks，它将是一个抽象类，带有抽象方法GetData。您将它们实例化为Rack的子类。然后，当你在Rack上调用GetData时，它会找到被覆盖的方法并调用它。这是一个例子。

abstract class Rack
{
   public abstract void GetData();
}

class ChildRack1 : Rack
{
    public override void GetData(){}
}

class ChildRack2 : Rack
{
    public override void GetData(){}
}

class Channel
{
    private Rack rack1;
    private Rack rack2;
    public Channel()
    {

    }

    public Channel(Rack h1, Rack  h2)
    {
        rack1 = h1;
        rack2 = h2;
    }

    public void send()
    {

        rack1.GetData();
    }

}

Answer 2

我认为这将为您提供所需的实施方案：

    class Channel
    {
        private List<Rack> racks;

        public Channel()
        {
            racks = new List<Rack>();
        }

        public Channel(params Rack[] racks)
        {
            this.racks = racks.ToList();
        }

        public void send()
        {
            foreach (Rack item in racks)
            {
                item.getData();
            }

        }

        public void SendSpecificRack(Rack rack)
        {
            //calls the getdata of the rack object passed
            rack.getData();
        }

    }

    public class Rack
    {
        public virtual void getData()
        {
            Console.WriteLine("Base Rack");
        }
    }

    public class RackChild1 : Rack
    {
        public override void getData()
        {
            Console.WriteLine("RackChild1");
        }
    }

    public class RackChild2 : Rack
    {
        public override void getData()
        {
            Console.WriteLine("RackChild2");
        }
    }

用法：

Channel chn = new Channel(new Rack[]{new RackChild1(),new RackChild2()});
chn.send();
RackChild2 rck = new RackChild2();
chn.SendSpecificRack(rck);

输出：

RackChild1
RackChild2
RackChild2

C＃中的动态强制转换

2 个答案: