PHP中数组的串行逗号

时间:2013-08-13 12:29:52

标签: php function native

我正在尝试从数组中创建字符串serial comma。这是我使用的代码:

<?php
    echo "I eat " . implode(', ',array('satay','orange','rambutan'));
?>

但我得到的结果是:

I eat satay, orange, rambutan

不能:

I eat satay, orange, and rambutan

然而!

所以,我创造了自己的功能:

<?php   
function array_to_serial_comma($ari,$konj=" and ",$delimiter=",",$space=" "){
    // If not array, then quit 
    if(!is_array($ari)){
        return false; 
    };
    $rturn=array();
    // If more than two 
    // then do actions
    if(count($ari)>2){
        // Reverse array
        $ariBlk=array_reverse($ari,false);
        foreach($ariBlk as $no=>$c){
            if($no>=(count($ariBlk)-1)){ 
                $rturn[]=$c.$delimiter;
            }else{
                $rturn[]=($no==0)? 
                    $konj.$c
                    : $space.$c.$delimiter; 
            };
        };
        // Reverse array
        // to original
        $rturn=array_reverse($rturn,false);
        $rturn=implode($rturn);
    }else{
        // If >=2 then regular merger 
        $rturn=implode($konj,$ari); 
    }; 
    // Return 
    return $rturn; 
 }; 
?>

因此:

<?php
    $eat = array_to_serial_comma(array('satay','orange','rambutan'));
    echo "I eat $eat";
?>

结果:

I eat satay, orange, and rambutan

是否有更有效的方法,可能使用本机PHP函数?

修改

基于@Mash的代码,我修改了可能有用的代码:

<?php
function array_to_serial_comma($ari,$konj=" and ",$delimiter=",",$space=" "){
    // If not array, then quit 
    if(!is_array($ari)){
        return false; 
    };
    $rturn=array();
    // If more than two 
    // then do actions
    if(count($ari)>2){
        $akr = array_pop($ari);
        $rturn = implode($delimiter.$space, $ari) . $delimiter.$konj.$akr;
    }else{
        // If >=2 then regular merger 
        $rturn=implode($konj,$ari); 
    }; 
    // Return 
    return $rturn; 
 }; 
?>

5 个答案:

答案 0 :(得分:8)

这是一个更清洁的方式:

<?php
    $array = array('satay','orange','rambutan');
    $last = array_pop($array);
    echo "I eat " . implode(', ', $array) . ", and " . $last;
?>

array_pop()从数组中取出最后一个元素并将其分配给$last

答案 1 :(得分:1)

<?php
    $arr = array('satay','orange','rambutan');
    print("I eat ".implode(", ", array_slice($arr, 0, count($arr)-1))." and ".$arr[count($arr)-1]);
?>

答案 2 :(得分:1)

试试这样:

$array = array('satay','orange','rambutan');
echo "I eat ".join(' and ', array_filter(array_merge(array(join(', ', array_slice($array, 0, -1))), array_slice($array, -1))));

重复问题:Implode array with ", " and add "and " before last item

答案 3 :(得分:0)

<?php
$arr = array('satay','orange','rambutan');
$lastElement = array_pop($arr);
echo "I eat " . implode(', ',$arr)." and ".$lastElement;
?>

这将导致相同的结果: 我吃沙爹,橘子和红毛丹

答案 4 :(得分:0)

这个怎么样?

function render_array_as_serial_comma($items) {
  $items = $variables['items'];

  if (count($items) > 1) {
    $last = array_pop($items);
    return implode(', ', $items) . ' and ' . $last;
  }
  return array_pop($items);
}

这应该做到以下几点:

echo render_array_as_serial_comma(array('a'));
echo render_array_as_serial_comma(array('a', 'b'));
echo render_array_as_serial_comma(array('a', 'b', 'c'));

a
a and b
a, b and c