Question

PHP

$meta = get_post_custom($post->ID); 
$images = $meta['img1'][0];    // urls separated with comma
$images = explode(',', $images);
foreach ($images as $image) {
    echo '{image : '.$image.', title : "Credit: x"},'; 
};

输出：

{image : 'http://localhost/slideshow/1.jpg', title : 'Credit: x'},
{image : 'http://localhost/slideshow/2.jpg', title : 'Credit: x'},
{image : 'http://localhost/slideshow/3.jpg', title : 'Credit: x'},
{image : 'http://localhost/slideshow/4.jpg', title : 'Credit: x'}, // last comma, just after }

我想删除输出中最后一个注释的逗号。

这正是我想要的：

期望的输出：

{image : 'http://localhost/slideshow/1.jpg', title : 'Credit: x'},
{image : 'http://localhost/slideshow/2.jpg', title : 'Credit: x'},
{image : 'http://localhost/slideshow/3.jpg', title : 'Credit: x'},
{image : 'http://localhost/slideshow/4.jpg', title : 'Credit: x'}

Answer 1

您可以将输出缓冲到变量并以这种方式解决：

echo rtrim($bufferedData, ',');

但正如我所看到的，最好使用json functions。

Answer 2

所以你的所有代码都是关于从你的数据创建JSON。那将是：

$data   = 'http://localhost/slideshow/1.jpg,http://localhost/slideshow/2.jpg,http://localhost/slideshow/3.jpg';
$credit = 'x';
$result = json_encode(array_map(function($image) use ($credit)
{
   return ['image'=>$image, 'Credit'=>$credit];
}, explode(',', $data)));
//var_dump($result);

Answer 3

您有很多选择：

// Using rtrim
$meta = get_post_custom($post->ID); 
$images = $meta['img1'][0];    // urls separated with comma
$images = explode(',', $images);
$string = '';
foreach ($images as $image) {
    $string .= '{image : '.$image.', title : "Credit: x"},'; 
};
$string = rtrim($string, ',');
echo $string;

// Using substring
$meta = get_post_custom($post->ID); 
$images = $meta['img1'][0];    // urls separated with comma
$images = explode(',', $images);
$string = '';
foreach ($images as $image) {
    $string .= '{image : '.$image.', title : "Credit: x"},'; 
};
$string = substr($string, 0, -1);
echo $string;

// Using implode
$meta = get_post_custom($post->ID); 
$images = $meta['img1'][0];    // urls separated with comma
$images = explode(',', $images);
$stringElements = array();
foreach ($images as $image) {
    stringElements[] = '{image : '.$image.', title : "Credit: x"}'; 
};

$string =  implode(',', $stringElements);
echo $string;

还要考虑使用更有效的方法来创建JSON字符串：json_encode。

Answer 4

也许这使用rtrim（）

$images = 'image1.png,image2.png,image3.png';
$ex = explode(',', $images);
foreach ($ex as $image) {
    $image_string .= "{'image' : '{$image}', 'title' : 'Credit: x'},"; 
}

print rtrim($image_string, ',');

以上返回

{'image' : 'image1.png', 'title' : 'Credit: x'},
{'image' : 'image2.png', 'title' : 'Credit: x'},
{'image' : 'image3.png', 'title' : 'Credit: x'}

从最后一个数组值中删除逗号

4 个答案: