我因此有一个数组
$main_array = [
["image" => "james.jpg", "name" => "james", "tag" => "spacey, wavy"],
["image" => "ned.jpg", "name" => "ned", "tag" => "bright"]
["image" => "helen.jpg", "name" => "helen", "tag" => "wavy, bright"]
]
我使用foreach
来基于tag
的值回显一些HTML。像这样
foreach($main_array as $key => $array) {
if ($array['tag'] == "bright") {
echo '<p>'.$array['name'].' '.$array['image'].' '.$array['tag'].'</p>';
}
}
这只会输出与标签“ bright”匹配的“ ned”。但是它也应该输出“ helen”。同样:
foreach($main_array as $key => $array) {
if ($array['tag'] == "wavy") {
echo '<p>'.$array['name'].' '.$array['image'].' '.$array['tag'].'</p>';
}
}
应输出“ james”和“ helen”。我需要什么样的功能才能达到预期的效果?
答案 0 :(得分:2)
在检查项目列表中的项目时,可以使用explode()
将其拆分为多个部分(我使用了", "
拆分,因为每个项目似乎也有空格),并且然后使用in_array()
检查它是否在列表中...
if (in_array("bright", explode( ", ", $array['tag']))) {
答案 1 :(得分:0)
您不能直接执行此操作,因为它会返回带有字符串值的键。下面是工作代码。
<?php
$main_array = [
["image" => "james.jpg", "name" => "james", "tag" => "spacey, wavy"],
["image" => "ned.jpg", "name" => "ned", "tag" => "bright"],
["image" => "helen.jpg", "name" => "helen", "tag" => "wavy, bright"]
];
foreach($main_array as $key => $array) {
$str_arr = explode (", ", $array['tag']);
foreach ($str_arr as $key2 => $array2) {
if ($array2 == "wavy") {
echo '<p>'.$array['name'].' '.$array['image'].' '.$array['tag'].'</p>';
}
}
}
?>