Question

我是Cocos2d的初学者，我想在离开屏幕5秒延迟时显示硬币精灵。所以这就是我在主游戏层中写的连续添加7个硬币的内容：

- (void)coinSidewaysRowOne { 
    if (coinSide1 == FALSE)
    {
        coinSide1 = TRUE;
        NSLog(@"coinSide1 = TRUE");
        int originalX = 500;
        for(int i = 0; i < 8; i++)
        {
            CCSprite *coinHorizontal = [CCSprite spriteWithFile:@"bubble.png"];
            coinHorizontal.position = ccp(originalX, 150);
            originalX += 20;

            [self addChild:coinHorizontal];
            [coinArray addObject:coinHorizontal];
        }
    }
}

然后，在我的updateRunning方法中，我添加了这个，所以当硬币在屏幕外产生时，它们向左移动并消失：

// Move coins off the screen and make them move away
    for (CCSprite *coin in coinArray) {
        // apply background scroll speed
        float backgroundScrollSpeedX = [[GameMechanics sharedGameMechanics] backGroundScrollSpeedX];
        float xSpeed = 1.09 * backgroundScrollSpeedX;

        // move the coin until it leaves the left edge of the screen
        if (coin.position.x > (coin.contentSize.width * (-1)))
        {
            coin.position = ccp(coin.position.x - (xSpeed*delta), coin.position.y);
        }
    }

所以现在，当我运行时，硬币从右侧移入并从左侧移出屏幕。如何制作它，以便当硬币向左移动并离开屏幕时，延迟5秒钟，然后让新硬币从右边回到屏幕，就像它最初那样。

谢谢！

Answer 1

您可以调用一个函数，将该精灵添加回屏幕，延迟时间为5秒。

您必须按如下方式添加一些代码：

for (CCSprite *coin in coinArray)
{
    // apply background scroll speed
    float backgroundScrollSpeedX = [[GameMechanics sharedGameMechanics] backGroundScrollSpeedX];
    float xSpeed = 1.09 * backgroundScrollSpeedX;

    // move the coin until it leaves the left edge of the screen
    if (coin.position.x > (coin.contentSize.width * (-1)))
    {
        coin.position = ccp(coin.position.x - (xSpeed*delta), coin.position.y);
    }
    else
    {
        [self performSelector:@selector(showSpriteAgain:) withObject:coin afterdelay:5.0f];
    }
}

并制作一个将该精灵再次添加到屏幕的功能：

-(void) showSpriteAgain:(CCSprite *)coin 
{
coin.position = ccp(coin.position.x+screenSize.width,coin.position.y);
}

我认为这就是你要找的东西。

显示延迟的CCSprites

1 个答案: