Question

尝试编译此代码时出现以下错误，为什么？

＆＃34; game.h：48：42：错误：'播放器'未命名类型

game.h：48：50：错误：ISO C ++禁止声明'敌人'，没有类型[-fpermissive]＆＃34;

第48行是函数＆＃34; fillMap＆＃34;顺便说一句

//game.h

#ifndef GAME_H
#define GAME_H

//CONSTANTS AND TEMPLATES

const int LEN = 40;

struct player
{
   char name[LEN]; //name of character
   char symbol; //character representing player on map
   int posx; // x position on map
   int posy; // y position on map
   bool alive; // Is the player alive
   double damage; // Player attacking power
   double health; // Player health
};

enum direction {LEFT, RIGHT, UP, DOWN};

//PROTOTYPES

//move amount specified in position structure
void moveAmount(player& pl, int posx, int posy);

//move to specified position on map
void moveTo(player& pl, int posx, int posy);

//one player attacking other
//returns whether attack was successfull
bool attack(const player & atacker, player & target);

//one player attacking a direction on the map, epl is a pointer to an array of enemies           players
//returns whether attack was sucessfull
bool attack(const player & pl, direction, player* epl);

//Check if player is dead, to be called inside attack function
inline bool isDead(const player& pl){
    return pl.health <= 0 ? 1 : 0;
}

//Remove player from map if he is dead
void kill(player& pl);

//Initialize map
void fillMap(const player& player, const player* enemies, int mapWidth, int mapHeigth);

//Display map
void displayMap(const int mapWidth, const int mapHeigth);

#endif

Answer 1

问题在于这一行：

void fillMap(const player& player, const player* enemies, int mapWidth, int mapHeigth);

由于您将player声明为参数，因此它仍然在整个前向声明的范围内。因此，其名称会影响类型名称player：在fillMap的转发声明中，player指的是第一个参数，而不是player类型。

将其重命名为pl以解决此问题：

void fillMap(const player& pl, const player* enemies, int mapWidth, int mapHeigth);

Answer 2

因为player不是类型; struct player是。

c ++ struct没有命名类型错误

2 个答案: