Question

我只是制作一个简单的猜谜游戏。如果用户输入0，我需要我的do-while循环退出。它的方式如果这是他们输入的第一个数字，它会正常退出，但是它只是增加，就像猜测数量的总和一样。这是我的代码：

System.out.println("The system will generate a random number between 1 and 100."
            + " Your goal is to guess this number.");
    do
    {

    Random secretNumberGen = new Random();
    int secretNumber = secretNumberGen.nextInt(100)+1;

    System.out.println("Enter a number between 1 and 100: ");
    guess = scan.nextInt();
    do
       {

        if(guess==secretNumber)
        {
            System.out.println("You guessed the number!");
        }
        else if(guess<secretNumber)
          {
         System.out.println("Your guess is too low! Guess again");
         numGuess++;
          }
        else if(guess>secretNumber)
          {
         System.out.println("Your guess is too high! Guess again");
         numGuess++;
          }
        else if(guess==0)
               break;
        System.out.println("Your number: \n");
        guess = scan.nextInt();
        guess++;
       }
    while(guess!=0&&guess!=secretNumber);

我猜我的while（）循环中的条件可能不正确。我稍微改变了它之前的状态，这是一段时间（猜测！= secretNumber）; 。也许这样做会更好，我们应该以不同的方式对待0？感谢。

Answer 1

问题是你增加了除第一个之外的所有猜测：

    System.out.println("Your number: \n");
    guess = scan.nextInt();
    guess++;

因此他们需要输入-1来猜测0并结束循环。他们还需要输入少于secretNumber的一个来进行正确的猜测....

Answer 2

为什么你需要在最后一行猜猜++？

删除猜测++或将其注释掉，你应该没问题

Answer 3

首先提出guess == 0条件。由于0小于任何生成的数字，因此它将首先进入该条件。

Answer 4

如果这是他们输入的第一个数字，它会正常退出，但除此之外它只会增加，如猜测数量的总和

这一行导致了这一点，据我所知，你的代码不需要：

guess++;

Answer 5

这是你应该做的： -

System.out.println("The system will generate a random number between 1 and 100."
        + " Your goal is to guess this number.");
do
{

Random secretNumberGen = new Random();
int secretNumber = secretNumberGen.nextInt(100)+1;

System.out.println("Enter a number between 1 and 100: ");
guess = scan.nextInt();
do
   {
    // Exit condition is being checked first so that control does not enter
    // the less-than-secret-number-condition which would always be true for zero
    if(guess==0)
         break;

    // If its not zero, num of guesses is to be incremented
    numGuess++;

    if(guess==secretNumber)
    {
        System.out.println("You guessed the number!");
        break; // Exits if it is zero or the secret number
    }
    else if(guess<secretNumber)
      {
     System.out.println("Your guess is too low! Guess again");
     // Commenting out the increment as its already done
     // numGuess++;
      }
    else if(guess>secretNumber)
      {
     System.out.println("Your guess is too high! Guess again");
     // Commenting out the increment as its already done
     // numGuess++;
      }

    System.out.println("Your number: \n");
    guess = scan.nextInt();
    // guess++ has been removed as I think it serves no purpose. numGuess is the variable maintaining the count

   }
while(true); // Changed the condition here as the exit conditions have already bee dealt with within the loop

当用户输入0时，无法弄清楚如何处理退出do-while循环

5 个答案: