我正在编写一个找到三角形斜边的程序,我需要让该程序运行任意次,直到用户输入2。我无法弄清楚如何在用户输入2时结束程序。 / p>
package assignment5a;
import java.util.Scanner;//import Scanner
public class Assignment5A {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);//new Scanner variable
int answer;
double side1, side2, result;
System.out.println("Enter 1 to calculate the hypotenuse of a triangle or enter 2 to quit.");
answer = sc.nextInt();
while(answer < 0 || answer > 2){
System.err.println("Please enter a valid answer.");
System.out.println("Enter 1 to calculate the hypotenuse of a triangle or enter 2 to quit.");
answer = sc.nextInt();
}
System.out.println("Enter side 1 of the triangle :");//input for side 1
side1 = sc.nextDouble();
System.out.println("Enter side 2 of the triangle :");//input for side 2
side2 = sc.nextDouble();
result = hypotenuse(side1, side2);//declares result as the result of the method hypotenuse
System.out.printf("Hypotenuse of your triangle is: %.2f%n", result);//prints results
}
public static double hypotenuse(double s1, double s2){//method for calculating hypotenuse
double hypot;
hypot = Math.sqrt((Math.pow(s1, 2) + Math.pow(s2, 2)));
return hypot;
}
}
答案 0 :(得分:1)
Wilmol的答案和Elliot Frisch的答案/评论只是解决方案的一半。
另一半是,您需要围绕大多数逻辑的外部循环,以便重复执行。将main()
的大部分放入使用while (true) {
开始的循环中,这样它将永远循环。
然后使用if (answer == 2) {
...的逻辑在用户输入2时实际中断。
答案 1 :(得分:0)
很少有选择:
if (answer == 2)
{
break;
}
if (answer == 2)
{
return;
}
if (answer == 2)
{
System.exit(0);
}
答案 2 :(得分:0)
所以我知道了。您的答案有很大帮助,但我最后放了两个while循环。代码如下:
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);//new Scanner variable
int answer;
double side1, side2, result;
System.out.println("Enter 1 to calculate the hypotenuse of a triangle or enter 2 to quit.");
answer = sc.nextInt();
while(answer < 0 || answer > 2){
System.err.println("Please enter a valid answer.");
System.out.println("Enter 1 to calculate the hypotenuse of a triangle or enter 2 to quit.");
answer = sc.nextInt();
}
while(answer == 1){
System.out.println("Enter side 1 of the triangle :");//input for side 1
side1 = sc.nextDouble();
System.out.println("Enter side 2 of the triangle :");//input for side 2
side2 = sc.nextDouble();
result = hypotenuse(side1, side2);//declares result as the result of the method hypotenuse
System.out.printf("Hypotenuse of your triangle is: %.2f%n", result);//prints results
System.out.println("Enter 1 to calculate the hypotenuse of a triangle or enter 2 to quit.");
answer = sc.nextInt();
}
} 公共静态双斜边(double s1,double s2){//计算斜边的方法
double hypot;
hypot = Math.sqrt((Math.pow(s1, 2) + Math.pow(s2, 2)));
return hypot;
}
}