Question

我有四个查询，每个查询有6列。每个查询都是相同的，除了WHERE子句在每种情况下略有不同。我希望看到的是每个查询的每个查询的结果，以便进行比较。

示例结果表标题：time（只有一个），calls1，calls2，calls3，calls4，work1，work2，work3，work4，tele1，tele2，tele3，tele4，comm1，comm2，comm3，comm4，techs1，techs2， techs3，techs4。

实际查询如下。请帮我做一个比较查询。 Ť

SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS r_calls, ROUND(AVG(work_time),2)/60 AS r_work, ROUND(AVG(tele_time),2)/60 AS r_tele, ROUND(AVG(comm_time),2)/60 AS r_comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS r_techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE call_origins_uid != 5 
AND DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15) 


SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS calls, ROUND(AVG(work_time),2)/60 AS work, ROUND(AVG(tele_time),2)/60 AS tele, ROUND(AVG(comm_time),2)/60 AS comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE call_origins_uid != 5 
AND DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
AND call_origins_uid = 1 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15)


SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS calls, ROUND(AVG(work_time),2)/60 AS work, ROUND(AVG(tele_time),2)/60 AS tele, ROUND(AVG(comm_time),2)/60 AS comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE call_origins_uid != 5 
AND DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
AND call_origins_uid = 4 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15)


SELECT CONCAT(hour(opened_dt),':',floor(minute(opened_dt)/15)*15) AS time, COUNT(*)/COUNT(DISTINCT DATE(opened_dt)) AS calls, ROUND(AVG(work_time),2)/60 AS work, ROUND(AVG(tele_time),2)/60 AS tele, ROUND(AVG(comm_time),2)/60 AS comm, IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3 AS techs 
FROM detail_head LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid 
WHERE DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY) 
AND dayname(opened_dt) = 'SUNDAY' 
GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15)

Answer 1

您可以为每个表使用'CREATE TEMPORARY TABLE TableName1'，然后编写一个查询以按顺序放置列，然后在完成后删除表。

加入四个具有相同列，不同条件的MySQL查询

1 个答案: