Question

我们假设我有这四个问题：

SELECT id_cre as credito, 
    data_eff as data, 
    '0.00' as incasso, 
    importo_fatt as spesa 
from fatture 
WHERE data_eff < '2014-12-31' 
UNION
SELECT id_cre as credito, 
    data_prev as data, 
    '0.00' as incasso, 
    importo_fatt as spesa 
from fatture 
WHERE data_prev >= '2014-12-31' 
UNION 
SELECT id_cre as credito, 
    data_prev as data, 
    importo as incasso, 
    '0.00' as spesa 
from incassi_prev 
WHERE data_prev >= '2014-12-31' 
UNION 
SELECT id_cre as credito, 
    data_inc as data, 
    importo_inc as incasso, 
    '0.00' as spesa 
from incassi_row 
WHERE data_inc < '2014-12-31'

我用它们来提取代码（信用卡）日期（数据）和金额），可以是收入（incasso）或费用（spesa）。

结果可以创建重复的行（具有相同代码但具有收入的行和具有费用的另一行）。如何重写查询以获得具有相同代码和日期的相同行收入和费用？我想用mysql做这个，因为我已经需要在javascript中遍历生成的数组，以按行重写表（每个代码作为一行，每个月作为一列）。

此外，有没有办法做同样的事情，但考虑同一个月/同一日期的两个不同日期（例如2014-12-20和2014-12-31）

谢谢！

Answer 1

尝试

SELECT credito, data, SUM(incasso) AS incasso, SUM(speca) AS speca
  FROM
(
  SELECT id_cre AS credito, data_eff AS data, 0.0 AS incasso, importo_fatt AS spesa 
    FROM fatture 
   WHERE data_eff < '2014-12-31' 
   UNION
  SELECT id_cre AS credito, data_prev AS data, 0.0 AS incasso, importo_fatt AS spesa 
    FROM fatture 
   WHERE data_prev >= '2014-12-31' 
   UNION 
  SELECT id_cre AS credito, data_prev AS data, importo AS incasso, 0.0 AS spesa 
    FROM incassi_prev 
   WHERE data_prev >= '2014-12-31' 
   UNION 
  SELECT id_cre AS credito, data_inc AS data, importo_inc AS incasso, 0.0 AS spesa 
    FROM incassi_row 
   WHERE data_inc < '2014-12-31'
) q
GROUP BY credito, data

将四个不同的查询合并为一个

1 个答案: