在MySQL中将表连接到同一领域的不同where条件？

Question

考虑以下表格：

account => ID, Login, Pass, Email, Level, IDNum, Name
records => RID, Status, IDNum, Reason, Type, Amount, Date, SubmitterID

现在我使用以下查询加入表：

SELECT account.Name FROM account, records WHERE records.IDNum = account.IDNum

在上面的查询中，名称字段将根据匹配的IDNum加入，但如果我想同时获取名称字段WHERE account.ID = records.ID和WHERE records.IDNum = account.IDNum，那么这可能吗？

简而言之，将下面的两个问题加入一个：

SELECT account.Name FROM account, records WHERE records.IDNum = account.IDNum
SELECT account.Name FROM account, records WHERE records.SubmitterID = account.ID

我可能不够清楚，请查看下面的示例数据：

显然，第一个查询的Name字段将返回John，并返回第二个查询的Chris。我想在一个查询中显示两个名称。

Answer 1

您实际上正在加入每个行，然后过滤掉只保留您想要的行。您应该使用连接过滤掉它们：

select account.Name
FROM account
    INNER JOIN records ON (records.IDNum = account.IDNum AND records.SubmitterID = account.ID)

编辑：通过OP问题编辑

在上面OR中，您似乎需要AND而不是JOIN。因此：

select account.Name
FROM account
    INNER JOIN records ON (records.IDNum = account.IDNum OR records.SubmitterID = account.ID)

编辑2：OP的评论后续跟进

create table account (id int, IDNum int, Name char(5));
insert into account values (1, 12345, 'John'), (2, NULL, 'Chris');
create table records (RID int, IDNum int, SubmitterID int);
insert into records values (1, 12345, 2);
select account.Name
FROM account
    INNER JOIN records ON (records.IDNum = account.IDNum OR records.SubmitterID = account.ID);

产量（使用MySQL 5.1.46）：

+-------+
| Name  |
+-------+
| John  |
| Chris |
+-------+

编辑3：通过OP第二评论：

这样的东西？

select account.Name as byIDNum, NULL bySubmitterID
from account
    inner join records USING (IDNum)
union
select NULL, account.Name
from account
    inner join records ON (records.SubmitterID = account.ID);

Answer 2

我可能会误解，但不会简单地完成你需要的东西吗？

SELECT account.name
FROM account, records
WHERE records.IDNum = account.IDNum
AND records.SubmitterID = account.id

或者，如果您想要返回以下任何一条规则都是真的：

SELECT account.name
FROM account, records
WHERE records.IDNum = account.IDNum
OR records.SubmitterID = account.id